flintmax

Largest consecutive integer in floating-point format

Description

example

f = flintmax returns the largest consecutive integer in IEEE® double precision, which is 2^53. Above this value, double-precision format does not have integer precision, and not all integers can be represented exactly.

example

f = flintmax(precision) returns the largest consecutive integer in IEEE single or double precision. flintmax returns single(2^24) for single precision and 2^53 for double precision.

Examples

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Return the largest consecutive integer in IEEE® double precision, 2^53.

format long e
f = flintmax
f =
9.007199254740992e+15

Return the largest consecutive integer in IEEE® single precision, single(2^24).

f = flintmax('single')
f = single
16777216

Check the class of f.

class(f)
ans =
'single'

Above the value returned by flintmax('single'), not all integers can be represented exactly with single precision.

Return the largest consecutive integer in IEEE® single precision, single(2^24).

f = flintmax('single')
f = single
16777216

Add 1 to the value returned from flintmax.

f1 = f+1
f1 = single
16777216

f1 is the same as f.

isequal(f,f1)
ans = logical
1

Add 2 to the value returned from flintmax. The number 16777218 is represented exactly in single precision while 16777217 is not.

f2 = f+2
f2 = single
16777218

Input Arguments

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Floating-point precision type, specified as 'double' or 'single'.

Data Types: char

Output Arguments

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Largest consecutive integer in floating-point format returned as a scalar constant. This constant is 2^53 for double precision and single(2^24) for single precision.