could anyone help me how to display the position of all the numbers present in matrix.

I am having a matrix A=[1 2 3 4;

5 6 7 8;

9 10 11 12]

could anyone help me how to display the position of all the numbers in matrix.

[Adam]

Give an example of what format you expect the output to be.

[Stephen23]

>> fprintf('val: %3d    pos: %3d\n',[A(:).';1:numel(A)])
val:   1    pos:   1
val:   5    pos:   2
val:   9    pos:   3
val:   2    pos:   4
val:   6    pos:   5
val:  10    pos:   6
val:   3    pos:   7
val:   7    pos:   8
val:  11    pos:   9
val:   4    pos:  10
val:   8    pos:  11
val:  12    pos:  12

If that is not what you want, then you need to explain your question better.

[jaah navi]

I want to have the result in the following order

value row column

     1     1    1
     5     2    1
     9     3    1
     2     1    2
     6     2    2
     10    3    2
     3     1    3
     7     2    3
     11    3    3
     4     1    4
     8     2    4
    12     3    4

Answer 1

[Fabio Freschi]

[iRow, jCol, value] = find(A);

then you can put them in a matrix, if you like

position = [value, iRow, jCol];

[Stephen23]

Note that this method will ignore zeros. Last time I checked, zero was still a number.

Answer 2

[Stephen23]

A simple method that includes all numbers (because zeros are also numbers):

>> A = [1,2,3,0;5,6,0,8;9,10,11,12]
A =
    1    2    3    0
    5    6    0    8
    9   10   11   12
>> S = size(A);
>> [R,C] = ndgrid(1:S(1),1:S(2));
>> [A(:),R(:),C(:)]
ans =
    1    1    1
    5    2    1
    9    3    1
    2    1    2
    6    2    2
   10    3    2
    3    1    3
    0    2    3
   11    3    3
    0    1    4
    8    2    4
   12    3    4