Suspensa Vix Via Fit

Answered

Convert cell array to vector

S = load('timestamps.mat'); T = vertcat(S.ans{:}) M = seconds(mean(diff(duration(T,'InputFormat','hh:mm:ss.SSS'))))

Convert cell array to vector

S = load('timestamps.mat'); T = vertcat(S.ans{:}) M = seconds(mean(diff(duration(T,'InputFormat','hh:mm:ss.SSS'))))

43 Minuten ago | 0

Answered

Maximum number of repeated values over an array

a = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,9]; x = cumsum([true;diff(...

Maximum number of repeated values over an array

a = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,2,0,0,0,0,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,9]; x = cumsum([true;diff(...

etwa 5 Stunden ago | 1

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Answered

How to compare greek letters if they are same

Rather than building maps by hand, I would get Python to do the heavy lifting, e.g.: baz = @(v)char(v(1)); % only need the firs...

How to compare greek letters if they are same

Rather than building maps by hand, I would get Python to do the heavy lifting, e.g.: baz = @(v)char(v(1)); % only need the firs...

etwa 7 Stunden ago | 0

Answered

How to convert time stamp 11:21:17.155 into seconds in MATLAB??

The most efficient solution: a = '11:21:17.155'; b = [60*60,60,1]*sscanf(a,'%f:')

How to convert time stamp 11:21:17.155 into seconds in MATLAB??

The most efficient solution: a = '11:21:17.155'; b = [60*60,60,1]*sscanf(a,'%f:')

ein Tag ago | 0

Answered

Is it possible to make a loop where the the result is separate from the loop and have the result respectively with the input?

Use a cell array to store the data: p = 'Quantity of product you have bought today: '; n = str2double(input(p,'s')); c = cell...

Is it possible to make a loop where the the result is separate from the loop and have the result respectively with the input?

Use a cell array to store the data: p = 'Quantity of product you have bought today: '; n = str2double(input(p,'s')); c = cell...

ein Tag ago | 0

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Answered

"If function" can't distinguish i ~= 1.6.

"This weird thing only happens when i=1.6." Nothing weird happens: you generate binary floating point numbers using two differe...

"If function" can't distinguish i ~= 1.6.

"This weird thing only happens when i=1.6." Nothing weird happens: you generate binary floating point numbers using two differe...

2 Tage ago | 1

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Answered

replacing loop with cell of index values

s = 1:100; c{1} = 1; c{2} = 1:5; c{3} = 2:2:10; out = cellfun(@(x)s(x),c,'uni',0); out{:} A well-written (i.e. correctly p...

replacing loop with cell of index values

s = 1:100; c{1} = 1; c{2} = 1:5; c{3} = 2:2:10; out = cellfun(@(x)s(x),c,'uni',0); out{:} A well-written (i.e. correctly p...

4 Tage ago | 1

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Answered

Colors in Matlab as a vriable

Perhaps something like this: M = [1,0,0;... red 1,1,0;... yellow 0,1,0]; % green X = strcmpi(Auto.Farbe,{'red','ye...

Colors in Matlab as a vriable

Perhaps something like this: M = [1,0,0;... red 1,1,0;... yellow 0,1,0]; % green X = strcmpi(Auto.Farbe,{'red','ye...

8 Tage ago | 0

Answered

Opening multiple .csv files using readtable

% opts is unchanged D = 'C:\Users\krist\OneDrive\Documents\MATLAB'; S = dir(fullfile(D,'*.csv')); for k = 1:numel(S) F =...

Opening multiple .csv files using readtable

% opts is unchanged D = 'C:\Users\krist\OneDrive\Documents\MATLAB'; S = dir(fullfile(D,'*.csv')); for k = 1:numel(S) F =...

8 Tage ago | 1

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Answered

How to create matrix with other matrixes by joining them?

a = [1 2 3]; b = [4 5 6]; c = [7 8 9]; d = [10 11 12]; res = reshape([a;c;b;d],2,[])

How to create matrix with other matrixes by joining them?

a = [1 2 3]; b = [4 5 6]; c = [7 8 9]; d = [10 11 12]; res = reshape([a;c;b;d],2,[])

9 Tage ago | 2

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Answered

saving the data in a variable

"...how to change the name of the file when matlab saves it" That is easy: https://www.mathworks.com/help/matlab/import_export...

saving the data in a variable

"...how to change the name of the file when matlab saves it" That is easy: https://www.mathworks.com/help/matlab/import_export...

9 Tage ago | 0

Answered

How to iterate over cell array, creating only unique combinations of cells

data = {1,2;3,4}; n = numel(data); m = nchoosek(1:n,2) % each row is one combination pair. out = data(m) % output [idr,idc] ...

How to iterate over cell array, creating only unique combinations of cells

data = {1,2;3,4}; n = numel(data); m = nchoosek(1:n,2) % each row is one combination pair. out = data(m) % output [idr,idc] ...

9 Tage ago | 0

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Answered

how to arrange data into array

Without an intermediate sparse array: R = [1;2;3;4]; C = [10;11;13;15]; V = [1e-5;5e-5;10e-5;15e-5]; % S = max([R,C],[],1);...

how to arrange data into array

Without an intermediate sparse array: R = [1;2;3;4]; C = [10;11;13;15]; V = [1e-5;5e-5;10e-5;15e-5]; % S = max([R,C],[],1);...

10 Tage ago | 0

Answered

How to count the number of times that values changes?

A = [1;1;1;2;1;3;3;1;1] B = [NaN;cumsum(diff(A)~=0)]

How to count the number of times that values changes?

A = [1;1;1;2;1;3;3;1;1] B = [NaN;cumsum(diff(A)~=0)]

11 Tage ago | 3

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Answered

Getting rid of loops

Logical indexing is much simpler than using loops: idx = A<1 & A>0; A(idx) = B(idx); A(A<C) = NaN; idy = B>100 | B<0; ...

Getting rid of loops

Logical indexing is much simpler than using loops: idx = A<1 & A>0; A(idx) = B(idx); A(A<C) = NaN; idy = B>100 | B<0; ...

11 Tage ago | 0

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Answered

How to conditionally merge rows in a table

lat = [45.67, 45.67, 56.89, 78.61]'; lon = [-66.45, -66.45, -65, -67]'; id = [202, 202, 201, 200]'; key = {'A', 'B', 'C', 'C'...

How to conditionally merge rows in a table

lat = [45.67, 45.67, 56.89, 78.61]'; lon = [-66.45, -66.45, -65, -67]'; id = [202, 202, 201, 200]'; key = {'A', 'B', 'C', 'C'...

12 Tage ago | 0

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Answered

Increment components of vector till a desired limit

for k = 6:100 % or 105 maybe... you can check this. v = reshape(hankel(1:5,5:k),1,[]) end

Increment components of vector till a desired limit

for k = 6:100 % or 105 maybe... you can check this. v = reshape(hankel(1:5,5:k),1,[]) end

12 Tage ago | 2

Answered

Expected one output from a curly brace or dot indexing expression but there were 2 results

For your code to work the index tn4 must be scalar, but the error message tells us that it is not. Compare: S(1).blah = 1:3; ...

Expected one output from a curly brace or dot indexing expression but there were 2 results

For your code to work the index tn4 must be scalar, but the error message tells us that it is not. Compare: S(1).blah = 1:3; ...

12 Tage ago | 0

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Answered

behaviour of nargout for anonymous functions

You get two different answers because you are testing two different functions: the function handle to addOne an anonymous func...

behaviour of nargout for anonymous functions

You get two different answers because you are testing two different functions: the function handle to addOne an anonymous func...

12 Tage ago | 0

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Answered

Combining cell arrays with empty doubles

% slightly more complex example data: a = {[],1;[],[]}; b = {[],[];2,[]}; c = {[],[];[],NaN}; % tmp = cat(3,a,b,c); [~,idp...

Combining cell arrays with empty doubles

% slightly more complex example data: a = {[],1;[],[]}; b = {[],[];2,[]}; c = {[],[];[],NaN}; % tmp = cat(3,a,b,c); [~,idp...

12 Tage ago | 2

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Answered

How to properly extract dataset and load in new file? Keep getting error.

There is no data field because you saved the array using the name Xs. So you need to use the field Xs (and get rid of the superf...

How to properly extract dataset and load in new file? Keep getting error.

There is no data field because you saved the array using the name Xs. So you need to use the field Xs (and get rid of the superf...

12 Tage ago | 0

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Answered

How do I insert data into new format based on row positions?

data = [8; 7; 1; 5]; datarowpositions = [0; 0; 0; 4; 0; 1; 0; 2; 0; 0; 3; 0]; desired = datarowpositions; desired(datarowposi...

How do I insert data into new format based on row positions?

data = [8; 7; 1; 5]; datarowpositions = [0; 0; 0; 4; 0; 1; 0; 2; 0; 0; 3; 0]; desired = datarowpositions; desired(datarowposi...

13 Tage ago | 0

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Answered

naming using a string function

The MATLAB approach: N = numel(files); C = cell(1,N); for k = 1:N F = fullfile(files(k).folder,files(k).name); C{k}...

naming using a string function

The MATLAB approach: N = numel(files); C = cell(1,N); for k = 1:N F = fullfile(files(k).folder,files(k).name); C{k}...

13 Tage ago | 0

Answered

how to iterate?

I don't see why any iterations are required, vectorized code will do this quite easily: A = [-120449852, -107496428]; B = [-10...

how to iterate?

I don't see why any iterations are required, vectorized code will do this quite easily: A = [-120449852, -107496428]; B = [-10...

13 Tage ago | 0

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Answered

Repeat a string with a delimiter

A = 'abc'; B = join(repmat({A},1,3),', '); B = B{1} C = join(repmat(string(A),1,3),', ') % string output! D = sprintf('%1$s,...

Repeat a string with a delimiter

A = 'abc'; B = join(repmat({A},1,3),', '); B = B{1} C = join(repmat(string(A),1,3),', ') % string output! D = sprintf('%1$s,...

13 Tage ago | 0

Answered

Remove parenthesis and the contents inside from a string

A = 'abc (ABC)'; B = regexp(A,'^\w+','once','match')

Remove parenthesis and the contents inside from a string

A = 'abc (ABC)'; B = regexp(A,'^\w+','once','match')

13 Tage ago | 0

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Answered

Programmatically change function input

Using a character vector is entirely the wrong approach. The correct approach is to use a comma-separated list: tt = synchroniz...

Programmatically change function input

Using a character vector is entirely the wrong approach. The correct approach is to use a comma-separated list: tt = synchroniz...

14 Tage ago | 0

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Answered

how can I display 3 row vectors as column vectors in front of eachother using fprintf?

a = [1,2,3]; b = [11,22,33]; c = [111,222,333]; fprintf('%d %d %d\n',[a;b;c])

how can I display 3 row vectors as column vectors in front of eachother using fprintf?

a = [1,2,3]; b = [11,22,33]; c = [111,222,333]; fprintf('%d %d %d\n',[a;b;c])

14 Tage ago | 0

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Answered

Find rows in cell for each array between two values and create new cell with the values you just found

Using linear indexing to access the cell arrays only requires one loop: n_new = cell(size(n)); for k = 1:numel(n) idx = f...

Find rows in cell for each array between two values and create new cell with the values you just found

Using linear indexing to access the cell arrays only requires one loop: n_new = cell(size(n)); for k = 1:numel(n) idx = f...

15 Tage ago | 0

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