How to supplement the matrix?

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Lev Mihailov
Lev Mihailov am 5 Jul. 2019
Kommentiert: Jan am 8 Jul. 2019
Hello! I cleaned my signal from emissions, it is in the form of a matrix, but there I used i-1, in consequence of which, instead of 1100, I now have 1099 values, how can I add the last value?\
for i = 1:length(d)-1 % Error 1100 1099
if g(i)-50>= g(i+1);
f(i)=g(i);
end
end
  6 Kommentare
Lev Mihailov
Lev Mihailov am 5 Jul. 2019
Cycle loop has nowhere
f = zeros(size(g));
% why do i need to convert to zeros?
The problem removed the outliers from the signal was 1099 values ​​(these are the positions of the maxima), but in the matrix there are 1100 values
Jan
Jan am 8 Jul. 2019
@Lev: |zeros()< does not convert anything to zeros. Please read the documentation:
doc zeros
to find out, that this is a pre-allocation of the output. Letting an array grow iteratively is extremely inefficient. Matlab has to allocation a new array in each iteration. So:
r = [];
for k = 1:1e6
r(k) = rand;
end
needs 8*1e6 bytes finally, but intermediately 8*sum(1:1e6) bytes are allocated: 4 TeraByte!
I do not understand the meaning of your comment. If you detect outliers by subtracting pairs elements, of course there is one element less in the output.

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Antworten (2)

dpb
dpb am 5 Jul. 2019
Adding to Stephen's answer Matlab syntax, the crystal ball says
for i = 1:length(d)-1 % Error 1100 1099
if g(i)-50>= g(i+1);
f(i)=g(i);
end
end
becomes
f=zeros(size(g));
ix=diff(g)<-50;
f(ix)=g(ix);

Lev Mihailov
Lev Mihailov am 5 Jul. 2019
Still nothing happened, gives an error
Index exceeds matrix dimensions.
  5 Kommentare
dpb
dpb am 5 Jul. 2019
c can only have length(d)-1 elements in it...as has been said multiple times before, preallocate it to the size wanted or compensate that there will always be one less array element since you're dealing with diff() functionality that produces one less element by its very nature.
dpb
dpb am 5 Jul. 2019
Bearbeitet: dpb am 5 Jul. 2019
In
for chek = 1:length(d)-1
if g(chek )-50>= g(chek +1);
c(chek )=10;
else g(chek )+50 <= g(chek +1);
c(chek)=g(chek );
end
end
the else clause should be elseif it appears.
What is the value for c if abs(diff(g))<50?
Again, use Matlab array syntax; the above loop construct (presuming the "elseif" and zero for then missing "else" clause)
c=zeros(size(g)); % preallocate to same size as g array
ix=diff(g)<-50;
c(ix)=10;
ix=diff(g)>=50;
c(ix)=g(ix);
You need to define what happens in the other cases not satisfied...if they're to remain unchanged, then use
c=g;
for initialization instead of zeros

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