division of two vectors

65 Ansichten (letzte 30 Tage)
mimalo salina
mimalo salina am 9 Okt. 2017
Beantwortet: mimalo salina am 9 Okt. 2017
What is the result of A/B ???? (if A and B are same 3x1 row vectors) Example:
A=[-1;1;7]
B=[5;7;-2]
A/B
in Matlab gives: ans =
0 -0.1429 0
0 0.1429 0
0 1.0000 0
  5 Kommentare
mimalo salina
mimalo salina am 9 Okt. 2017
Bearbeitet: mimalo salina am 9 Okt. 2017
yes, but A ,B are same 3x1 row vectors, it seems false, because , we can't divide two vectors? i want to undersand the meaning of this result !
Guillaume
Guillaume am 9 Okt. 2017
Bearbeitet: Guillaume am 9 Okt. 2017
"we can't divide two vectors". Well, obviously you can apply the / operators to two vectors since matlab give you a result.
As Adam said in his comment and as Jan showed in its answer, what it does is fully documented. It solves a system of linear equation. If the right-hand side is not a square matrix as is the case here, it is solved using least-square method. As documented:
If A is a rectangular m-by-n matrix with m ~= n, and B is a matrix with n columns, then x = B/A returns a least-squares solution of the system of equations x*A = B
I'm not sure what other answer you are looking for.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Jan
Jan am 9 Okt. 2017
C = A / B determines the matrix C such that:
C * B = A
Try it:
A = [-1;1;7];
B = [5;7;-2];
C = A / B;
C * B
>> [-1; 1; 7]

Weitere Antworten (2)

John D'Errico
John D'Errico am 9 Okt. 2017
A=[-1;1;7];
B=[5;7;-2];
First of all, A and B are NOT row vectors. They are column vectors. Thus, A is a vector in column orientation.
A
A =
-1
1
7
Next, what is C=A/B?
C = A/B
C =
0 -0.142857142857143 0
0 0.142857142857143 0
0 1 0
It is a matrix, such that if possible, we will have A=C*B.
C*B
ans =
-1
1
7
In some cases of vectors or matrices of varying sizes, that will not be possible.

mimalo salina
mimalo salina am 9 Okt. 2017
Action closed.
Thanks a lot for all your answers!
Kind regards.

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by