Interpolation of 3D point data
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shellmcg
am 19 Apr. 2016
Kommentiert: Adam Danz
am 19 Dez. 2019
Hello, I have a nx5 matrix where column 3, 4 and 5 are x,y,z 3D points respectively. I was wondering how I would interpolate (smooth) this 3D data. Many thanks
4 Kommentare
Walter Roberson
am 20 Apr. 2016
What properties does the curve need to have? Are you looking for a spline fit? A pchip fit?
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John D'Errico
am 29 Apr. 2016
Bearbeitet: John D'Errico
am 29 Apr. 2016
You can use my interparc tool, as found on the file exchange. It is designed to solve exactly this problem, in 2 or more dimensions.
xyz = interparc(1000,x,y,z,'spline');
xyz will be a 1000x3 array, where each row is an interpolated point on the curve.
Of course, you can do the interpolation in other ways. If you want to do the work in MATLAB yourself in much the same way as you tried to do it:
t = [0;cumsum(sqrt(diff(x).^2+diff(y).^2+diff(z).^2))];
t = t/t(end);
ti = linspace(0,1,1000);
xx = spline(t,x,ti);
yy = spline(t,y,ti);
zz = spline(t,z,ti);
The above solution, which uses a cumulative piecewise linear arclength as the parameter for interpolation, deals more properly with points that are not uniformly spaced.
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Weitere Antworten (2)
Walter Roberson
am 20 Apr. 2016
It looks to me as if you likely want a scattered interpolant.
shellmcg
am 28 Apr. 2016
1 Kommentar
John D'Errico
am 28 Apr. 2016
Bearbeitet: John D'Errico
am 29 Apr. 2016
I'm sorry, but this answer is just a poor way of solving the problem, presuming the points are somehow equally spaced. Use of a spline as was done here can cause some strange artifacts.
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