How to shuffle rows in pairs?
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Hello. I have a 600 x 1 matrix. They can have only 8 values, let's say 1, 2, 3, 4, 5, 6, 7, and 8. I want to randomize the order of the rows but in pairs so 1 is always followed by 2, and 3 is always followed by 4, 5 is always followed by 6, and 7 is always followed by 8. Like there were only 4 elements: 1-2, 3-4, 5-6, and 7-8. But in pairs in rows (within the same column).
One case: if we have
1
2
3
4
5
6
7
8
One of the many randomizations would be:
5
6
1
2
7
8
3
4
Thank you!
2 Kommentare
Image Analyst
am 23 Mär. 2022
I don't understand how the 600 and 8 relate to each other. So do the numbers 1-8 repeat each other for rows 9-16, 17-24, etc. up to 593-600? Do you want the shuffling to occur totally within the band, like rows 1-8 must still be in rows 1-8 and rows 593-600 must still be in rows 593-600? Or can any row end up anyplace except that the following row must also be moved so that it's following it in its new row location?
Antworten (2)
Arif Hoq
am 23 Mär. 2022
Bearbeitet: Arif Hoq
am 23 Mär. 2022
try this:
A=randi([1 8],600,1);
for i=1:size(A,1)
if A(i)==1
A(i+1)=2;
elseif A(i)==3
A(i+1)=4;
elseif A(i)==5
A(i+1)=6;
elseif A(i)==7
A(i+1)=8;
end
end
4 Kommentare
Jan
am 23 Mär. 2022
I'm not sure what the purpose of your code is. A shorter version:
for i = 1:size(A,1)
if A(i) < 8
A(i+1) = A(i) + 1;
end
end
This might append an element and is not a random shuffling.
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