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Carlos Guerrero García


Last seen: 5 Monate vor Aktiv seit 2022

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Beantwortet
sketch the graph of the function: f(x,y)= 1+2x^2+2y^2
The usage of polar coordinates must be useful: [rho,theta]=meshgrid(0:0.1:2,0:pi/60:2*pi); x=rho.*cos(theta); y=rho.*sin(thet...

etwa 2 Jahre vor | 0

Beantwortet
How do I plot the following function? (I don't have syms function either)
I recommend the usage of the commando called "plot3" r= ... % range for r ux =0.*r % ux must be a vector uy = -0.125.*r+1.125...

etwa 2 Jahre vor | 0

Beantwortet
how can I use partfrac command?
I suggest the following code: syms s; laplace(ilaplace((8*s^2+37*s+32)/((s+1)*(s+2)*(s+4))))

etwa 2 Jahre vor | 0

Beantwortet
Draw 3D object.write code in 2016a version. Help me,thanks!
Is the same question that https://es.mathworks.com/matlabcentral/answers/430986-draw-3d-object-code-this-in-2016a-version-help?...

etwa 2 Jahre vor | 0

Beantwortet
Draw 3D object. code this in 2016a version.help!
Is this the same question that https://es.mathworks.com/matlabcentral/answers/430684-draw-3d-object-write-code-in-2016a-version...

etwa 2 Jahre vor | 0

Beantwortet
How to draw D in 3D ?
There is a wrong sign in the KSVV isolation of z in the first equality, and so, the D1 definition must be D1=(4-X^2-Y^2).^0.5 ...

etwa 2 Jahre vor | 0

Beantwortet
Problem in x and y trajectory.
After the first (x,y,z)=(1,0,1) assignment, the lines before velocity states (X,Y,Z)=(-10,-280; 280-8/3)=(-10,-280,832/3), and s...

etwa 2 Jahre vor | 0

Beantwortet
How can I graph the following parametric functions on a 3d graph?
And...what about an animation? [THETA,PHI]=meshgrid(0:2*pi/60:2*pi,0:pi/60:pi); for R=0.1:0.01:2; mesh(R.*cos(THETA).*sin...

etwa 2 Jahre vor | 0

Beantwortet
scatter3 plot to a mesh plot or surface plot
I don't know what kind of surface do you want to add...perhaps something like this??? x = [0 -9 9 0 -9 9 0 -9 9 0 -9 9 0 -9 9];...

etwa 2 Jahre vor | 0

Beantwortet
how do you graph z=sqrt(9-r^2cos^2(theta))?
I think that Carter Pennington was talking about the parametrized surface x=r*cos(theta) y=r*sin(theta) z=sqrt(9-r^2*(cos(the...

etwa 2 Jahre vor | 0

Beantwortet
How do I plot x^2+z^2=9 above the xy plane and between y=-1 and y=2?
The z definition z=sqrt(9-x^2) is not for the below part of the surface. I prefer not using symbolic variables for the represent...

etwa 2 Jahre vor | 0

Beantwortet
Integral for the outer surface area of the part of hyperboloid formed by a hyperbola
Here I post the graph of the two-sheet hyperboloid, using the following lines. I hope it will be useful for another surface of r...

etwa 2 Jahre vor | 0

Beantwortet
Problems with truncated top of the graph
In the line axis([0 6000 0 6000 0 2500]) delete the limits in the z-axis, i.e. use the following line instead: axis([0 6000 0...

etwa 2 Jahre vor | 0

| akzeptiert

Beantwortet
integral2 error, bu the function works
A sketch of the function: [x,y]=meshgrid(0:0.01:1); % The region in the statement surf(x,y,1-exp(-0.01*abs(x-y))); % Plotting ...

etwa 2 Jahre vor | 0

Beantwortet
Integral2 Error message
syms x y; int(int(x/y+y/x,1,2),1,4) vpa(ans)

etwa 2 Jahre vor | 0

Beantwortet
How to fix errors within double integral.
For plotting the region, I suggest the following code: x=-3:0.05:3; % Setting up the range of X y=sqrt(9-x.^2); % Calculating ...

etwa 2 Jahre vor | 0

Beantwortet
Having problems with this triple integral
The exercise ask for the evaluation using cylindrical coordinates and you're not using cylindrical coordinates in your code. Als...

etwa 2 Jahre vor | 0

Beantwortet
calculating Double integral over a region
When you define "fun", the variable "aa" is undefined yet. Also, because the variables "x" and "y" doesn't appear in the "fun" d...

etwa 2 Jahre vor | 0

Beantwortet
Error in the script
If you put the title and then plot without "hold on" you never see the title (swap title and plot instructions), but your error ...

etwa 2 Jahre vor | 0

Beantwortet
sin(x)^2
Perhaps the following lines will be useful: syms x; % Establishing 'x' as a symbolic variable combine(sin(x)^2,'sincos') % For...

etwa 2 Jahre vor | 0

Beantwortet
how can I find the surface area and the volume through this code?
The surface which area (and volume) is found, can be visualized using the following code: v =[2;0;1;9;0;1;3;0;1]; % Line in the...

etwa 2 Jahre vor | 1

Beantwortet
How to plot sin(xy)=sin(x)+sin(y)?
"contour" command provides another way to plot an implicit function defined by an expression like F(x,y)=0. For the implicit fun...

etwa 2 Jahre vor | 1

Beantwortet
please help me plot this two odefunction yy'+36x=0 and xy'=y^2+y
Your goal is not clear for me, but I try to help. Because we can separate the varaibles in both odes, the general solution of th...

etwa 2 Jahre vor | 0

| akzeptiert

Beantwortet
Find the value of a
Hi Trenton...!!! You can find my suggestion for an animation plot in https://es.mathworks.com/matlabcentral/answers/593245-fin...

etwa 2 Jahre vor | 0

Beantwortet
Plotting a section of a hemisphere using parametric equations
Another way for changing the theta and/or phi values is theta=[0:pi/36:2*pi]; phi=[0:pi/36:pi/4]; Anyway, I suggest not to cr...

mehr als 2 Jahre vor | 0

Beantwortet
Matlab to LaTeX
And what about matlab2tikz ???

mehr als 2 Jahre vor | 0

Beantwortet
how to fix my code and how to find the area of the regon
The area can be found as follows (the explanation can be found in any Calculus text. I think that here is not the right place fo...

mehr als 2 Jahre vor | 0

Beantwortet
How to compute the area of cardioid r=2(1+cosx)
I think that you only need a graph (to be included in the statement of an exercise, example,...) I hope the following code will...

mehr als 2 Jahre vor | 0

Beantwortet
AREA OF POLAR CURVE
I think you're talking about the area of a region bounded by a polar curve (the area of a region bouuded by a curve, not the are...

mehr als 2 Jahre vor | 0

Beantwortet
HELP! Double integration set up!
Just use the "vpa" instruction (variable precision arithmetic) after your script: syms x y int(int(exp(1)^x,x,1,log(y)),1,exp(...

mehr als 2 Jahre vor | 0

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