Error in the script

I was creating a graph where the system says "Variable y_div must be of size [1 2001]. It is currently of size [1 1]. Check where the variable is assigned a value."

Idk whats wrong

x = -1 : 0.001 : 1;

y_div = (x.^2) / (1 + (x.^2));
title ('División acotada');
plot (x, y_div);

subplot (3,1,1);

Answer 1

[Walter Roberson]

A/B is approximately A*pinv(B) where the * is inner product (algebraic matrix multiplication). When both sides are column vectors the result is a scalar.

You need the division operator, which is ./ not /

Answer 2

[Torsten]

x = -1 : 0.001 : 1;
y_div = (x.^2) ./ (1 + (x.^2));
title ('División acotada');
plot (x, y_div);

Answer 3

[Carlos Guerrero García]

If you put the title and then plot without "hold on" you never see the title (swap title and plot instructions), but your error is the dot before "/". Try with the following lines:

In Spanish: Si pones el título antes de "plot" sin poner "hold on" entonces no te aparecerá el título. Para arreglar eso, te propongo hacer primero "plot" y luego poner el título, pero tu error está en el punto antes de la división. Prueba con lo siguiente:

x = -1:0.001:1;
y_div =(x.^2)./(1+(x.^2));
plot(x, y_div);
title('División acotada')

[Carlos Guerrero García]

I thnik you're showing that the function f(x)=x^2/(1+x^2) is a bounded one. If I'm right, I suggest the usage of a bigger interval. Perhaps [-10,10] will be better than [-1,1]. I suggest the following lines:

x = -10:0.001:10;
y_div =(x.^2)./(1+(x.^2));
plot(x, y_div);
title('División acotada')

[Haowei Zhang]

Gracias, es que lo sabia hacer esto pero de repente se me olvido de eso xD.