Find minimum and maximum from same matrix

2 Ansichten (letzte 30 Tage)
Ajit Bashyal
Ajit Bashyal am 14 Jul. 2021
Kommentiert: Ajit Bashyal am 16 Jul. 2021
I have a matrix of 1181*101 that is a Power of an electric vehicle. It has positive, negative and zeros. Now I need to choose minimum of positive from total matrix and maximum of negative from the same total matrix. How can I do it?
Example
i=1181, j=101
% Power =[1181*101] containing both positive, negative and zeros.
% Now,
if Power(i, j) >= 0
[P, index] = min(Power, [], 2);
else
%(i.e. Power(i,j)<0)
[P, index] = max(Power, [], 2);
But every time, either it is taking only minimum or only maximum at a time. I tried changing negative terms to zero for minimum and positive terms to zero for maximum, but it still did not work. Please help me.
I can email to you if you require more details like code and variables.
  3 Kommentare
Image Analyst
Image Analyst am 14 Jul. 2021
You can attach the variables right here. Why not make it easy for people to help you, not hard? Why make us go through an extra step to get your matrix when you could have just attached it in a .mat file right here when you originally posted?
Ajit Bashyal
Ajit Bashyal am 16 Jul. 2021
This is the attached file. One more question to Jan, can't i write it in the same variable name like minPositive and maxNegative making a same name as minmax or something like that? And yes I need to neglect the zero because it doesnot have any use.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Jan
Jan am 14 Jul. 2021
I guess, that zeros values should be ignored. Then:
tmpPower = Power;
tmpPower(tmpPower <= 0) = Inf;
[minPositive, index1] = min(tmpPower, [], 2);
tmpPower = Power;
tmpPower(tmpPower > 0) = -Inf;
[maxNegative, index2] = max(tmpPower, [], 2);

Weitere Antworten (1)

David Hill
David Hill am 14 Jul. 2021
m=yourMatrix;
m(m<=0)=inf;
Min=min(m,[],'all');
m=yourMatrix;
m(m>=0)=0;
Max=-max(abs(m),[],'all');

Kategorien

Mehr zu MATLAB finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by