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how to assign zero value to all pixels in an image ?

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sheno39
sheno39 am 11 Sep. 2013
assign zero value to pixel

Akzeptierte Antwort

Jan
Jan am 11 Sep. 2013
It depends on what an "image" is. Please post more details in future questions. Fortunately the procedure to set the values to 1 is equal:
Img = rand(1024, 768, 3); % RGB image
Img(:) = 0;
Img2 = randi([0, 255], 1024, 768, 'uint8');
Img2(:) = 0;
  2 Kommentare
sheno39
sheno39 am 11 Sep. 2013
thanks a lot. as am beginner in matlab programming, i do not how to do the code.. i need the code for following function: function computedensity() for x in all pixels p[x] = 0; for n in all pixels less than 3 p[x]+=exp(-(f[x]-f[n])^2
Jan
Jan am 12 Sep. 2013
Bearbeitet: Jan am 12 Sep. 2013
This is a completely new question. Please ask it in a new thread.
"for n in all pixels less than 3 " is not clear to me. What is "f"?

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Weitere Antworten (2)

sidra
sidra am 11 Sep. 2013
I don't understand what purpose setting all the pixel values to zero would achieve.
Nevertheless One of the method is:
You can use two for loops starting from 1 to you image size and the within these loops set the pixel values to zero. Something of this sort
for i=1:n
for j=1:m
img(i,j)=0;
end
end
where n and m are the number of rows and columns respectively.
  2 Kommentare
sheno39
sheno39 am 11 Sep. 2013
thanks for your answer.. how to code the following.. kindly reply.. function computedensity() for x in all pixels p[x] = 0; for n in all pixels less than 3 p[x]+=exp(-(f[x]-f[n])^2
Image Analyst
Image Analyst am 11 Sep. 2013
% Find all pixels < 3
binaryImage = f < 3; % binaryImage is what you called x
Now, what's f(n)? What is n? In f(x), x is all pixels less than 3. But what is n in f(n)?

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Image Analyst
Image Analyst am 11 Sep. 2013
Yet another way
grayImage = zeros(size(grayImage), 'uint8');
  1 Kommentar
sheno39
sheno39 am 11 Sep. 2013
Bearbeitet: sheno39 am 11 Sep. 2013
thanks for your help.. can u help me to code the following.. kindly reply.. function computedensity() for x in all pixels p[x] = 0; for n in all pixels less than 3 p[x]+=exp(-(f[x]-f[n])^2

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