How can I use while loops to determine if an element is larger than the element below it and store the results in a vector with 1 representing true and 0 representing false?

4 Ansichten (letzte 30 Tage)
I coded for my while loop but I can't get the final answer and the error showed that 'Array indices must be positive integers or logical values.' Can someone help me with this? Thank you so much!!
A=randi([0 9],1,randi([100 300]))'
n=numel(A)-1
B=zeros(n,1)
while i<=n
if A(i)>A(i+1)
B(i,1)=true
else
B(i,1)=false
end
i=i+1
end

Akzeptierte Antwort

Matt J
Matt J am 26 Mär. 2021
A=randi([0 9],1,10)';
n=numel(A)-1;
B=zeros(n,1);
i=1;
while i<=n
if A(i)>A(i+1)
B(i,1)=true;
else
B(i,1)=false;
end
i=i+1;
end
A.',B.'
ans = 1×10
0 2 1 8 0 9 4 2 6 2
ans = 1×9
0 1 0 1 0 1 1 0 1

Weitere Antworten (1)

John D'Errico
John D'Errico am 26 Mär. 2021
Bearbeitet: John D'Errico am 26 Mär. 2021
"While" this does not answer your question, I would not use a while loop at all. Learn to use MATLAB as it is designed.
A = randn(1,8) % some random numbers
A = 1×8
-0.2087 0.3007 -0.3599 -0.0566 0.4045 -3.0370 -0.3818 0.8694
B = [false,diff(A)>0] % A vector of the same length as A, true when A(i+1) > A(i)
B = 1×8 logical array
0 1 0 1 1 0 1 1
B is the same length as A. Note that A(1) will never be greater than the preceding element, since there is no preceding element.
Could you use a while loop? Yes. A for loop would make more sense as a loop here, since you want to test EVERY pair of elements.
B = false(size(A)); % preallocate B
for ind = 2:numel(A)
B(ind) = A(ind) > A(ind-1);
end
B
B = 1×8 logical array
0 1 0 1 1 0 1 1
Same result as the single statement, but a loop.
CAN you use a while loop? Well, yes. Learn when to use one type of loop over another when you REALLY need to use a loop. A while loop is good when you don't know how often the loop will run. A for loop is right when you have a known, fixed number of iterations.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by