sort a matrix without using sort function

how can I sort this matrix in descend order(only columns) without using sort function (my homework). for example: A= [
17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9 ]
to
B=[
24 17 15 8 1
23 16 14 7 5
22 20 13 6 4
. . . . . .. . .
.. .. . .. . .. . ]
thanks

3 Kommentare

John
John am 22 Jan. 2013
thanks for your help ,I was able to get this script work. thank your very much.
Cedric
Cedric am 22 Jan. 2013
+1 for the "homework" tag! If other students were as honest as that, they would get more of my time ;-)

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Antworten (1)

Jan
Jan am 22 Jan. 2013
Bearbeitet: Jan am 1 Okt. 2017

1 Stimme

Here a solution, which I would not submit except with a bold explanation:
B = zeros(size(A));
n = size(A, 2);
for iRow = 1:size(A, 1)
v = A(iRow, :);
while any(diff(v) > 0) % Test if sorted in descending order
v = v(randperm(n, n)); % If not, shuffle the elements randomly
end
B(iRow, :) = v;
end
This is based on the "infinite monkey" theorem: Even a randomly typing monkey will find the solution by accident. In consequence is not guaranteed to finish until your homework is due.
[EDITED] This is not a serious suggestion. If you deliver this as solution of a homework, you might get an extra point for a nerdy kind of humor, perhaps. Ask an internet search engine for better sorting algorithms.

6 Kommentare

Pame
Pame am 1 Okt. 2017
Old post, but what does v(randperm(n)); actually do?
Stephen23
Stephen23 am 1 Okt. 2017
Bearbeitet: Stephen23 am 1 Okt. 2017
The line
v = v(randperm(n));
randomly shuffles the elements of v. You can read the randperm documentation to know what it does.
Pame
Pame am 1 Okt. 2017
Bearbeitet: Pame am 1 Okt. 2017
Doesen't randperm(n) create an array with random integers from 1 to size(A,2) and with as many elements as the second dimension of matrix A? I don't see how it makes sense to take v(this randperm list).
Btw, is it possible to rewrite this script a bit to make it sort rows in ascending order instead? I know the while any(diff(v) > 0) line makes it not work for ascending numbers, and i haven't found a good while condition for ascending rows.
Jan
Jan am 1 Okt. 2017
Bearbeitet: Jan am 1 Okt. 2017
@Pame: This code shuffles the elements of each row vector randomly until it is ordered correctly - by accident. This is a hilarious sorting method and I have suggested it, because the OP did not show any own effort. When this was a homework question, we can assume that John has heard something about sorting in the lessons already. Even a short search in the internet will reveal many many examples for (better) sorting algorithms.
I'm not sure if you asking seriously for the opposite sorting direction, or if this is ironical. If you are really interested in this detail, change
any(diff(v) > 0)
to
any(diff(v) < 0)
Pame
Pame am 2 Okt. 2017
I like the insertion sort method, and i've got it to work for arrays, but not for matrixes.
Also currently trying to make a function which sorts matrixes in ascending order so that the lowest value element is in (1,1) and the highest value element is in the last row, last column.
Jan
Jan am 2 Okt. 2017
But "matrices" are "arrays". Do you mean "vectors"?
Do you have a question? If so, I recommend to open a new thread.

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