Hi all,
have this bit of code that reads:
function R = resistors()
r = transpose(100:100:400);%transpose to column vector
R = 1./((1/r)); % (.) makes the vector even
end
and its results read;
>> resistors
ans =
Inf Inf Inf 400
i want to stop or not have the Inf, but the real numbers, can someone point me in the right direction? need it for an assesment.
Thanks
Jon

3 Kommentare

darova
darova am 12 Mär. 2020
1/(1/r)
Is the same as just r
>> r = 1:5
r =
1 2 3 4 5
>> 1./(1./r)
ans =
1 2 3 4 5
Jonathan Stanton
Jonathan Stanton am 12 Mär. 2020
cheers, works lovely!!
Stephen23
Stephen23 am 12 Mär. 2020
"1/(1/r) Is the same as just r"
This is totally incorrect.
How is solving systems of linear equations anything like calculating the inverse?

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Stephen23
Stephen23 am 12 Mär. 2020
Bearbeitet: Stephen23 am 12 Mär. 2020

1 Stimme

You used the wrong operator: mrdivide / solves a system of linear equations.
You need to learn the differrences between matrix operations and array operations, otherwise all of your MATLAB code will produce meaningless rubbish outputs:
Use rdivide ./

2 Kommentare

John D'Errico
John D'Errico am 12 Mär. 2020
Bearbeitet: John D'Errico am 12 Mär. 2020
In my hoped for new post as official WhiteHouse MATLAB counsel, I will recommend that infs and NaNs be forever outlawed. They only confuse people anyway. I might even try to require that pi==3, as this would make many computations much simpler for children in school. By the way, the Earth will soon be mandated to be flat, if I get my way.
My campaign is beginning today. Please get your write-in votes in as soon as possible!

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Mathematics finden Sie in Hilfe-Center und File Exchange

Tags

Gefragt:

am 12 Mär. 2020

Bearbeitet:

am 12 Mär. 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by