Cycle counting from 0

I have a matrix [ 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0] for exemple

I'd like to have an outing:

2 x 4 "0" in succession

2 x 2 "0" in succession

1 x 3 "0" in succession

How to program it

Thank you.

[Image Analyst]

I have no idea what you want. What is an "outing"? Do you mean output? If so, what is the output array you want? I can't tell from your word descriptions. Type it out in numbers like you did for the input matrix.

[Stephen23]

stefan's "Answer" moved here:

With this matrix : [ 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 1 1 1 1 1 0 0 0 0 0 ]

I would have liked to have this matrix :

|5 2|

|6 1|

|4 1|

With the 1st column the number of successive 0

With the 2nd column the number of the sequence

thanks

Answer 1

[Stephen23]

>> M = [0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,0,0,0,0,1,1,1,1,1,0,0,0,0,0];
>> D = diff([false;M(:)==0;false]);
>> L = find(D<0) - find(D>0);
>> [U,~,X] = unique(L,'stable');
>> V = histc(X,1:max(X));
>> Z = [U(:),V(:)]
Z =
     5     2
     6     1
     4     1

[Stephen23]

stefan's "Answer" moved here:

Thanks, it's good

I have another question:

I would like to know the number of times we have the torque (1,4) in the vector [ 0 0 0 1 1 1 2 2 2 1 1 1 1 4 4 4 4 4 1 1 4 4 4 4 4 4 2 2 4 4 4]

The answer is 2 in this case

[Stephen23]

"I have another question:"

What have you tried so far?

[Stephen23]

stefan's "Answer" moved here:

To be more precise:

I have a vector that can have values from 1 to 15.

I would like to know the number of times for all the possible changes:

for example:

from 1 to 2

from 2 to 11

from 14 to 3

....

[Stephen23]

Try using diff.

[stefan]

Diff isn't the good fonction :

from 2 to 3 and from 3 to 4, I don't have the couples (1,2) and (2,3). I just know that there are passages from an N value to an N+1 value.

[Stephen23]

"I have a vector that can have values from 1 to 15. I would like to know the number of times for all the possible changes: for example:"

from 1 to 2
from 2 to 11 
from 14 to 3
....

None of your provided data includes the values 11 or 14, so you are asking me to help you on an unknown algorithm with unknown data. Sorry, but my magic crystal ball is not working today.

"from 2 to 3 and from 3 to 4, I don't have the couples (1,2) and (2,3)."

Well, that makes two of us, because I don't have them either! Nor do you explain what they are, or how they relate to 1, 2, 11, 14, and 3 from your previous comment, or the binary data of your original question.

One clear explanation of the method/algorithm (complete with input and output example data) would actually mean that you get the help that you are looking.

[stefan]

it's a new question.

For example with this matrix:[1 1 1 1 12 12 2 3 2 3 4 5 2 1 10 13 13 14 14 14 14 ]

in output, I would have liked to have as an output vector:

1 12 1

12 2 1

2 3 2

3 1 1

3 4 1

4 5 1

5 2 1

2 1 1

1 10 1

10 13 1

13 14 1

with :

1st column: 1st number

2nd column: 2nd number

2nd column: number of times we have the couple (1st number, 2nd number)

Answer 2

[Akira Agata]

How about the following?

x = [0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 1 1 1 0 0 0 0 1 1 1 1 1 0 0 0 0 0];

str = num2str(x')';
c = regexp(str,'0+','match');
len = cellfun(@numel,c);
output = [(1:max(len))', accumarray(len',1)];

The result becomes like this:

>> output

output =

1 0

2 0

3 0

4 1

5 2

6 1

[Stephen23]

stefan's "Answer" moved here:

that's not what I expect:

if I look at the matrix:

there are 2 sequences with 5 consecutive zeros

there is 1 sequence with 6 consecutive zeros

and there are 1 sequences with 4 consecutive zeros

the output matrix is:

5 2

6 1

4 1

[Akira Agata]

You mean, the order is also important?

My output is same as what you expected, except the order of rows and including 0 sequence cases (such as 1~3 consecutive zeros).