structure contains multiple cells with different variables in them I would like to remove variables not present in all cells
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Mithilesh Rajendrakumar
am 12 Nov. 2019
Kommentiert: Mithilesh Rajendrakumar
am 13 Nov. 2019
my structure (data) contains 1x3 cells horizontally. Each cell inturn contains three 1x1 structures with about 165 variables in each of them (The number of variables is not constant). I am trying to compare all variables names within these cells and then remove variables not present in all cells. This is so I can concatinate all the variables within these cells hoizontally. Below is a piece of code I have written to identify all the fieldnames from a structure called data and then concatenate them vertically. problem arises when there are missing variables, which I would then like to remove if not found on all cells within data.
flds = fieldnames(data{1,1});
for f = 1:size(flds,1)
out(f,:) = eval(['[data{1,1}.', flds{f} ,' ', 'data{1,2}.', flds{f} ,' ', 'data{1,3}.', flds{f} ,']']);
end
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Guillaume
am 12 Nov. 2019
Bearbeitet: Guillaume
am 12 Nov. 2019
%identify common fields
commonfields = fieldnames(data{1});
for cidx = 2:numel(data)
commonfields = intersect(commonfields, fieldnames(data{cidx}));
end
%keep only the common fields in each structure
trimmeddata = cell(size(data));
for cidx = 1:numel(data)
scell = struct2cell(data{cidx}); %convert to cell for easy extraction
[tokeep, fieldindex] = ismember(fieldnames(data{cidx}), commonfields); %which rows of cell array to keep and which order to use for commonfields
trimmeddata{cidx} = cell2struct(scell(tokeep, :), commonfields(fieldindex(tokeep)), 1); %convert back into structure
end
merged = [trimmeddata{:}];
3 Kommentare
Guillaume
am 12 Nov. 2019
Fixed, I'd forgotten to remove the indices (0) of fields to discard from fieldindex.
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