Interweave two arrays in a specific pattern

I have two column vectors each of which is 160 rows long. I want to interweave them such that the first 16 rows of vector 2 are underneath the first 16 rows of vector 1, the second 16 rows of vector 2 are underneath the original second 16 rows of vector 1 and so on. E.g. the vectors are interweaved in alternating blocks of 16. Is there a simple way to do this?

Answer 1

[Fangjun Jiang]

%%
a=(1:32)';
b=(10:10:320)';

%%
c=reshape([a,b],16,[]);
d=c(:,[1:2:end,2:2:end]);
e=d(:)

%% better solution from Guillaume
c=[reshape(a,16,[]);reshape(b,16,[])];
e=c(:)

[Guillaume]

May be simpler:

reshape([reshape(a, 16, []); reshape(b, 16, [])], [], 1)  %reshape a and b separately into columns of 16 rows. Vertically concatenate the two and reshape back into vector

[Fangjun Jiang]

Apparently, it is better! Thanks!

Answer 2

[Daniel M]

x = [1:160]';
y = x;
xx = reshape(x,16,[])';
yy = reshape(y,16,[])';
zz = [xx,yy]';
z = zz(:);

[Guillaume]

None of the (conjugate!) tranpose are necessary. Simply use zz = [xx; yy]

[Daniel M]

details....details...

% edited:
% your starting point, x and y are two column vectors
x = [1:160]';
y = x

%
xx = reshape(x,16,[]); % put into matrix of 16 rows, N columns
yy = reshape(y,16,[]);
zz = [xx,yy]; % vertically concatenate
z = zz(:); % column vector again

Note: the two answers are now identical.