Keeping Previous Iteration changes

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Nelson Gonzalez
Nelson Gonzalez am 26 Okt. 2019
Kommentiert: Adam Danz am 12 Dez. 2019
I am trying to change the user inputted text with the apropriate index of cipher vector. However, i cant seem to be able to keep the changes from the previous iterations of the for loop. How can i keep the changes with each iteration?
cipherVector = ['D','R','I','U','S','Y','A','Q','B','W','T','E','Z','N','L','P','M','O','C','V','H','G','F','J','X','K'];
letterVector = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
userEncrypt = input('Enter sentence','s')
for i= 1: strlength(userEncrypt)
if ismember(lower(userEncrypt(i)), letterVector)
x = strrep(userEncrypt, userEncrypt(i), cipherVector(strfind(letterVector,lower(userEncrypt(i)))))
end
end
  4 Kommentare
Rena Berman
Rena Berman am 12 Dez. 2019
(Answers Dev) Restored edit
Adam Danz
Adam Danz am 12 Dez. 2019
Thank you Rena Berman

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Antworten (1)

Fabio Freschi
Fabio Freschi am 27 Okt. 2019
I see two problems in your code
1) the changes are only temporarily saved in x and x is never used
2) onec you change a letter, all the characters with that letter are changed, than the cypherLetter is changed again. For example if your sentence is 'aaa', after the first iteration you get 'DDD' and the second D is then processed at the second iteration.
I changed your code like this
cipherVector = ['D','R','I','U','S','Y','A','Q','B','W','T','E','Z','N','L','P','M','O','C','V','H','G','F','J','X','K'];
letterVector = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'];
userEncrypt = input('Enter sentence: ','s');
for i= 1: strlength(userEncrypt)
% find position
iPos = find(letterVector==lower(userEncrypt(i)));
if ~isempty(iPos)
userEncrypt(i) = cipherVector(iPos);
end
end
disp(userEncrypt)
I hope this meets your initial request

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