how to reduce the use of repeated for loops as i explained below???
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
M.Prasanna kumar
am 22 Aug. 2019
Kommentiert: M.Prasanna kumar
am 23 Aug. 2019
when SS =1 , KK loop should not take the value from 1 to 3
when SS = 2:23 , KK loop should not run for SS-1:SS+1
when SS =24 , KK loop should not take the value from 22 to 24
to calculate the variable "dist" i used three sets of for loops. is it possible to reduce
I am able to get the answer but i dont want to repeat the same code for three times. how to resolve the problem???
for ss = 1
for kk = setdiff(1:no_receivers+1,1:3)
for ii = 1:no_gridsx
dist(ii,1:250,kk,ss) = sqrt((apert_x(1,ss)-X(ii,1:250)).^2+(apert_y(1,ss)-Y(ii,1:250)).^2)+sqrt((X(ii,1:250)-apert_x(1,kk)).^2+(Y(ii,1:250)-apert_y(1,kk)).^2);
end
end
end
for ss = 2:23
for kk = setdiff(1:no_receivers+1,ss-1:ss+1)
for ii = 1:no_gridsx
dist(ii,1:250,kk,ss) = sqrt((apert_x(1,ss)-X(ii,1:250)).^2+(apert_y(1,ss)-Y(ii,1:250)).^2)+sqrt((X(ii,1:250)-apert_x(1,kk)).^2+(Y(ii,1:250)-apert_y(1,kk)).^2);
end
end
end
for ss = 24
for kk = setdiff(1:no_receivers+1,22:24)
for ii = 1:no_gridsx
dist(ii,1:250,kk,ss) = sqrt((apert_x(1,ss)-X(ii,1:250)).^2+(apert_y(1,ss)-Y(ii,1:250)).^2)+sqrt((X(ii,1:250)-apert_x(1,kk)).^2+(Y(ii,1:250)-apert_y(1,kk)).^2);
end
end
end
2 Kommentare
Akzeptierte Antwort
Rik
am 22 Aug. 2019
Use a temporary variable to adapt your range. The code below show one such approach.
%intitialize for testing
no_gridsx=10;
no_receivers=26;
ss_max=24;
dist=NaN(no_gridsx,250,no_receivers+1,ss_max);
for ss = 1:ss_max
skips=ss-1:ss+1;
if ss==1%correct for edge cases
skips=skips+1;
elseif ss==ss_max
skips=skips-1;
end
for kk = setdiff(1:no_receivers+1,skips)
for ii = 1:no_gridsx
dist(ii,1:250,kk,ss) = ...
sqrt((apert_x(1,ss)-X(ii,1:250)).^2+(apert_y(1,ss)-Y(ii,1:250)).^2) ...
+sqrt((X(ii,1:250)-apert_x(1,kk)).^2+(Y(ii,1:250)-apert_y(1,kk)).^2);
end
end
end
4 Kommentare
Stephen23
am 23 Aug. 2019
Bearbeitet: Stephen23
am 23 Aug. 2019
"why did you subtract ss==24 & add ss==1 , what is the logic behind this"
(ss-1:ss+1)-(ss==24)+(ss==1)
%^^^^^^^^^^ creates a vector, exactly like you did
% ^^^^^^^^^ when ss==24 subtracts 1 from the vector
% ^^^^^^^^ when ss==1 adds 1 to the vector
With setdiff this provides exactly the vectors described on the first three lines of your question.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu GPU Computing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!