Could anyone help me to solve the issue in the following code.
Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
Ältere Kommentare anzeigen
U =[0 0.0987 0 0 0.0767;
0 0.0141 0 0 0.0184]
V =[0 0.2948 0 0 0.2310;
0 0.4909 0 0 0.4257]
for v =1:size(V,2)
for u =1:size(U,1)
A(u,v) =((U(u-1,v-1)).*(V(u,v)))-sum((V(1:u-1,v)).*(U(u-1,v-1)))
end
end
In this code the expression A(u,v) does not need to perform for first row but it needs to be performed for second row.
Coud anyone please help me to solve this.
5 Kommentare
Adam
am 29 Jul. 2019
Why not just start the u loop from 2 instead of 1 then?
jaah navi
am 29 Jul. 2019
Adam
am 29 Jul. 2019
How did you manage to get that far if you don't know how to start a for loop from 2?!
You explicitly start your for loop from 1, just replace that with a 2
for u =2:size(U,1)
doc for
tells you more about for loops and how to specify them, but you seem to knnow this anyway, having written the code at the top!
jaah navi
am 29 Jul. 2019
Adam
am 29 Jul. 2019
Just initialise
A = V;
before the loop as this appears to be the end result you want.
You should make it clear in the question what end result you want though. There is no reason for us to assume that you want the first row to be equal to that of V when you just say " does not need to perform for first row"
Antworten (2)
Dvir Haberman
am 29 Jul. 2019
0 Stimmen
As Adam pointed out in the comments section: it seems like you're accessing index 0 of a MATLAB array. Unlike C, Python and others array indices in MATLAB starts in 1.
You could precalculate the first element and start your for loop from 2.
To start you loops from 2 simply do
for v =2:size(V,2)
for u =2:size(U,1)
A(u,v) =((U(u-1,v-1)).*(V(u,v)))-sum((V(1:u-1,v)).*(U(u-1,v-1)))
end
end
remember that you need to precalculate the first elements
1 Kommentar
jaah navi
am 29 Jul. 2019
Guillaume
am 29 Jul. 2019
What I actually need is the ouput should be as follows:
[ 0 0.2948 0 0 0.2310;
0 (0.4909-0.2948)*0.0987 0 0 (0.4257-0.2310)*0.0767]
[0 0.2948 0 0 0.2310;
0 0.0775 0 0 0.0149]
Hum,
>> (0.4909-0.2948)*0.0987
ans =
0.019355
not 0.0775.
Assuming the v-1 were a mistake and the offset was only on the rows, this is equivalent to the expression you wrote in your question and doesn't require loops:
A = [V(1, :); U(1:end-1, :) .* (V(2:end, :) - cumsum(V(1:end-1, :), 1))]
Diese Frage ist geschlossen.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!