Filter löschen
Filter löschen

For loop with a big matrix of 800 MB

5 Ansichten (letzte 30 Tage)
Trung Ngo
Trung Ngo am 26 Jun. 2019
Bearbeitet: Trung Ngo am 27 Jun. 2019
Hi all,
I am searching through a big matrix file ( nearly 850 MB) and tried to loop through that matrix but it take a massive amount of time. I wonder if are there any method to run a simple for loop in this "big data" matrix. My code is at belown
clearvars;
load('landorocean_250_W.mat')
tA_world = tall(A_world);
tx_world = tall(x_world);
ty_world = tall(y_world);
[m_1,n_1]=size(A_world);
for i=1:m_1
for j=1:n_1
if gather(tA_world(i,j) == -32768)
island_250m_1(i,j)=0;
else
island_250m_1(i,j)=1;
end
end
end
Thank you for your time,
Sincerely,
  4 Kommentare
Jan
Jan am 27 Jun. 2019
@Trung Ngo: In the opriginal question you wrote ">800mb". Of course this might mean 800 TeraByte also. Then only a tall array can catch this. Please post the maximum size and how much free RAM you have. It matters of ">800MB" means 850MB on a computer with 8GB of RAM, or if it means 800GB on a machine with 2 GB RAM.
Trung Ngo
Trung Ngo am 27 Jun. 2019
@Jan: Sorry for being unclear. It is 850MB matrix under a computer with 16GB RAM.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Guillaume
Guillaume am 26 Jun. 2019
Bearbeitet: Guillaume am 26 Jun. 2019
Using gather as you have done on each individual element of the tall array completely nullifies the advantage of tall arrays. You may as well not have used tall arrays, it would have been faster.
The loop was not needed in the first place:
island_250m_1 = tA_world == -32768; %creates a tall array the same size as tA_world
%now you can call gather if you want to convert that tall array into a concrete array
island_250m_1 = gather(island_250m_1);

Weitere Antworten (0)

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Produkte


Version

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by