putting the answer in a matrices
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I have matrix a. Then, I find which column in each row has number bigger than 1. The code is as below
a =
5 0 0 0 0 0 0 0 0 0
3 1 0 0 0 0 0 0 0 0
1 2 0 0 0 0 0 0 0 0
1 0 1 0 0 0 0 0 0 0
>> for cpart=1:size(a,1)
b=a(cpart,:);
row = find(b ~=0)
end
row =
1
row =
1 2
row =
1 2
row =
1 3
How can I put the row in a matrices ?(as shown below)
row = [1 0
1 2
1 2
1 3]
1 Kommentar
Image Analyst
am 25 Feb. 2019
What are you going to do if you have row? Because I'm thinking you don't even need it and whatever you're going to do can be done much easier with a mask
mask = a~=0; % Create a logical 2-D matrix.
So I don't want to tell you how to get row if it just makes things more complicated for what you eventually want to do. So, what will you do with row if you had it?
Akzeptierte Antwort
Weitere Antworten (1)
madhan ravi
am 25 Feb. 2019
b=arrayfun(@(x)find(a(x,:)),1:size(a,1),'un',0);
M=max(cellfun('prodofsize',b));
C=cellfun(@(x)[x zeros(1,M-numel(x))],b,'un',0);
Result=vertcat(C{:})
1 Kommentar
madhan ravi
am 25 Feb. 2019
To remove rows with all zeros:
Result(sum(Result,2)~=0,:)
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!