Hi. I am a complete novice at matlab and have been asked to create a 10x10 matrix in as few steps as possible. The first row has to be from 1:10, the second line from 2:11 and so on. How can I create this using repmat?
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Sam Thorpe
am 21 Feb. 2019
Kommentiert: Sam Thorpe
am 22 Feb. 2019
%this is the matrix I want to achieve
A = zeros(10)
A(1,:)=[1:10]
A(2,:)=[2:11]
A(3,:)=[3:12]
A(4,:)=[4:13]
A(5,:)=[5:14]
A(6,:)=[6:15]
A(7,:)=[7:16]
A(8,:)=[8:17]
A(9,:)=[9:18]
A(10,:)=[10:19]
%How can I achieve this using repmat, reshape or meshgrid and the colon
%operator?
1 Kommentar
Stephen23
am 22 Feb. 2019
"How can I achieve this using repmat, reshape or meshgrid and the colon operator?"
Are those really the only operators you are allowed to use?
Akzeptierte Antwort
Fangjun Jiang
am 21 Feb. 2019
(1:10)+(0:9)'
Weitere Antworten (3)
Stephen23
am 22 Feb. 2019
This uses meshgrid and plus as well (not sure if that is allowed):
>> [X,Y] = meshgrid(0:9,1:10);
>> X+Y
ans =
1 2 3 4 5 6 7 8 9 10
2 3 4 5 6 7 8 9 10 11
3 4 5 6 7 8 9 10 11 12
4 5 6 7 8 9 10 11 12 13
5 6 7 8 9 10 11 12 13 14
6 7 8 9 10 11 12 13 14 15
7 8 9 10 11 12 13 14 15 16
8 9 10 11 12 13 14 15 16 17
9 10 11 12 13 14 15 16 17 18
10 11 12 13 14 15 16 17 18 19
0 Kommentare
madhan ravi
am 22 Feb. 2019
Honestly Fangjun Jiang's answer is the way I would do it but according to your question "How can I create this using repmat?" Which I think is a complete waste of time.
repmat(1:10,numel(1:10),1)+repmat((0:9).',1,numel(0:9))
3 Kommentare
madhan ravi
am 22 Feb. 2019
True we should wait:
Another possibilty:
(0:9).' can be replaced with reshape(0:9,1,[])
Jos (10584)
am 22 Feb. 2019
Bearbeitet: Jos (10584)
am 22 Feb. 2019
I think this is the only acceptable answer is, given all restraints:
A = reshape([1:10 2:11 3:12 4:13 5:14 6:15 7:16 8:17 9:18 10:19],10,10)
which does not use numel, tranpose (.'), semi-colons, and plus :-D
But wait a minute, ... is concatenation using square brackets acceptable or not ...
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