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how to find the index for the following code
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If A=1:10,%A= 1 2 3 4 5 6 7 8 9 10
But I want to display the index of A using for loop.
Could anyone help me to solve the issue.
3 Kommentare
Rik
am 19 Feb. 2019
Can't you just use A as an index?
someData=[5 8 7 4 6 9 3 10 7 2];
A=5;
disp(someData(5))%shows the 5th element (6 in this case)
%or in a loop:
for A=1:10
disp(someData(A))
end
Antworten (1)
madhan ravi
am 20 Feb. 2019
Bearbeitet: madhan ravi
am 20 Feb. 2019
“But I want to display the index of A using for loop”
You don’t need one , see the documentation of fprintf().
Values=rand(1,10); % example data
A=1:numel(Values); %indices
fprintf('When A = %d the value is %d\n',[A;Values])
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