Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
I need some assistance with my function program?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I'm not sure where my mistakes are. The following is my main program:
a = input('Enter value for side a: ');
if a <= 0
disp('Not a valid input! Side "a" must be greater than zero.');break;
end
b = input('Enter value for side b: ');
if b <= 0
disp('Not a valid input! Side "b" must be greater than zero.');break;
end
c = input('Enter value for side c: ');
if c <= 0
disp('Not a valid input! Side "c" must be greater than zero.');break;
end
if a > b+c
fprintf('\n');
disp('Error: Side "a" must be less than the sum of sides b & c.');break;
elseif b > a+c
fprintf('\n');
disp('Error: Side "b" must be less than the sum of sides a & c.');break;
elseif c > a+b
fprintf('\n');
disp('Error: Side "c" must be less than the sum of sides a & b.');break;
end
fprintf('\n');
[Angle_A,Angle_B,Angle_C] = angle_calc(a,b,c) % This is the correct name of my function program
My function program is:
function [law_cosines] = angle_calc (side_A,side_B,side_C)
angle_A = acosd((b^2+c^2-a^2)/(2*b*c));
angle_B = acosd((a^2+c^2-b^2)/(2*a*c));
angle_C = acosd((a^2+b^2-c^2)/(2*a*b));
0 Kommentare
Antworten (2)
Image Analyst
am 22 Jul. 2012
Your "function program" needs to look like this:
function [angle_A, angle_B, angle_C] = angle_calc (a, b, c)
angle_A = acosd((b^2+c^2-a^2)/(2*b*c));
angle_B = acosd((a^2+c^2-b^2)/(2*a*c));
angle_C = acosd((a^2+b^2-c^2)/(2*a*b));
0 Kommentare
Walter Roberson
am 22 Jul. 2012
Your line
function [law_cosines] = angle_calc (side_A,side_B,side_C)
should be
function [angle_A, angle_B, angle_C] = angle_calc (side_A,side_B,side_C)
10 Kommentare
Image Analyst
am 22 Jul. 2012
Well because he didn't list the actual error (like Jan noted) I actually had to copy and paste, fix it up a little, and run it to find out the error. This should have been discovered immediately by Aaron, particularly if he knew how to use the debugger (which is always faster than debugging via Answers postings).
Diese Frage ist geschlossen.
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!