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How I can create a three dimensional succession

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ric1321
ric1321 am 6 Jan. 2019
Kommentiert: Stephen23 am 6 Jan. 2019
Hi to everyone! What I would like to know is how I can define a 1x1xN element considering that in the third dimension I would like to have something like:
freq = (5:0.5:15)*1e9;
I hope I've been clear enough!

Akzeptierte Antwort

Stephan
Stephan am 6 Jan. 2019
freq(1,1,:) = (5:0.5:15)*1e9;
  2 Kommentare
ric1321
ric1321 am 6 Jan. 2019
Thank you!
Stephen23
Stephen23 am 6 Jan. 2019
Note that this is fragile, and can throw an error if freq already exists in the workspace and has an incompatible size.

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Weitere Antworten (2)

John D'Errico
John D'Errico am 6 Jan. 2019
Bearbeitet: John D'Errico am 6 Jan. 2019
As simple as one line like this:
freq = reshape((5:0.5:15)*1e9,1,1,[]);
As you can see, it has the desired shape.
size(freq)
ans =
1 1 21

madhan ravi
madhan ravi am 6 Jan. 2019
N=numel(freq);
f=zeros(1,1,N);
f(:,:,:)=freq

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