How does one store all the words from a loop into a variable?

for j = 1:length(wordsB)
PositionB = Shuffle2 (j); % Use number from the random array
% wordsB (PositionB); % Assign random position to words in text file
RandomWordsB = wordsB(PositionB);
% RandomWordsB = wordsB(PositionB); %Assign the obtained list to a varible to be displayed
disp (RandomWordsB) %display the random word list
end
RandomWords = [RandomWordsA; RandomWordsB]; %combining words from both arrays
disp (RandomWords) %display the random word lists

2 Kommentare

It would have been easier for people to help you if you had attached the text files.
...or at least format the code using alt+enter.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

madhan ravi
madhan ravi am 15 Dez. 2018
You can store them as cells like below:
RandomWordsA=cell(1,numel(wordsA));
for i = 1:length(wordsA)
PositionA = Shuffle1 (i); % Use number from the random array
% wordsA (PositionA); % Assign random position to words in text file
RandomWordsA{i} = wordsA(PositionA); %Assign the obtained list to a varible to be displayed
disp (RandomWordsA) %display the random word list
end
celldisp(RandomWordsA)

2 Kommentare

It didn't exactly work out but it did help me reach the right answer! Thank you!
Anytime :) , glad you found some way.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

RandomWordsA(i) = wordsA(PositionA); %Assign the obtained list to a varible to be displayed
and
RandomWordsB(j) = wordsB(PositionB);
We cannot tell what datatype you are working with, but I suspect that to get the 12 x 2 array that you want, you will need to change
RandomWords = [RandomWordsA; RandomWordsB]; %combining words from both arrays
to
RandomWords = [RandomWordsA(:), RandomWordsB(:)]; %combining words from both arrays

1 Kommentar

Hmm that didn't quite work, I'm looking to somehow add to RandomWordB, every new element created by the loop

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Gefragt:

am 14 Dez. 2018

Bearbeitet:

am 20 Dez. 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by