Filter löschen
Filter löschen

How to repeat the first number only

1 Ansicht (letzte 30 Tage)
fyza affandi
fyza affandi am 7 Dez. 2018
Bearbeitet: Stephan am 2 Jan. 2019
Array a is given
a =[1]
How can I add 0 to the array depending on n.
n=1 --> a=[0 1]
n=2 --> a=[0 0 1]
n=3 --> a=[0 0 0 1]
and n can be changes to any number

Akzeptierte Antwort

madhan ravi
madhan ravi am 7 Dez. 2018
Bearbeitet: madhan ravi am 7 Dez. 2018
a = 1;
n = 2; % just an example n
a = [zeros(1,n) a]
  2 Kommentare
fyza affandi
fyza affandi am 7 Dez. 2018
Thank you very much :)
madhan ravi
madhan ravi am 7 Dez. 2018
Bearbeitet: madhan ravi am 7 Dez. 2018

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Image Analyst
Image Analyst am 7 Dez. 2018
madhan's way is the best (how I'd do it), but I just want to show you a neat trick - that you can "grow" an array by simply assigning something to the last location (the location at the largest point that you want to grow it to):
a = 1; % Initial array.
n = 2; % just an example n
% a = [zeros(1,n) a] % Best way
a(n+1) = 0; % Enlarge array by appending zeros simply by assigning the last element.
a = fliplr(a) % Flipr it so that the 1 is on the right.
  5 Kommentare
Stephen23
Stephen23 am 7 Dez. 2018
Bearbeitet: Stephen23 am 7 Dez. 2018
Not just a neat trick, until R2015b allocating to the last element (and implicitly filling array with zeros) was faster than calling zeros:
Stephan
Stephan am 2 Jan. 2019
Bearbeitet: Stephan am 2 Jan. 2019
49996 +2

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by