How do I insert a variable text string in matlab plot?

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Vikash Pandey
Vikash Pandey am 13 Nov. 2018
Bearbeitet: madhan ravi am 14 Nov. 2018
Part of my code is
d_close = 3*(r1_eq + r2_eq)
figure(101);
h1 = plot(normalized_time, r1_us, 'b-', normalized_time, r2_us, 'k:');
set(h1,'linewidth',2);
txt = ['d = ', num2str(d_close)];
% t = text(0.0025, 17, txt);
t.FontSize = 24;
legend(['Bubble-1'], ['Bubble-2'])
and so on...
I wish to put sort of additional "third" legend for a plot that has two curves (r1_us and r2_us versus normalized time) only. So, I had to opt for string-method to put the additional information on the plot. But when I run the code, I get the error
Unable to perform assignment because dot indexing is not supported for variables of this type.
Error in bubble_mettin_solver (line 25)
t.FontSize = 24;
So how do I fix this? Please help. I wish that every time the plot shows up it has the information of updated d_close value.
By the way can I have a third legend in which there are only two curves? I know how to implement variable legend, but not the text.
  6 Kommentare
Stephen23
Stephen23 am 13 Nov. 2018
Get rid of these square breckets:
legend(['Bubble-1'], ['Bubble-2'])
They do nothing useful whatsoever:
Vikash Pandey
Vikash Pandey am 13 Nov. 2018
Agreed. removed but currently I am facing another issue.

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madhan ravi
madhan ravi am 13 Nov. 2018
Bearbeitet: madhan ravi am 14 Nov. 2018
t=text(0.2, 21, ['d = ' num2str(d_close)]);
t.FontSize = 34;
Vikash pandey's solution:
txt = text(0.03, 21, ("$d =\mbox{ }$" + d_close*1d6 + "$\mu m$"),'Interpreter','latex');
txt.FontSize = 28;
  19 Kommentare
Vikash Pandey
Vikash Pandey am 14 Nov. 2018
Madhan. I found the solution to the problem from a user in Stackoverflow. The solution is:
txt = text(0.03, 21, ("$d =\mbox{ }$" + d_close*1d6 + "$\mu m$"),'Interpreter','latex');
txt.FontSize = 28;
madhan ravi
madhan ravi am 14 Nov. 2018
wow that's cool!

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Weitere Antworten (2)

Jan
Jan am 13 Nov. 2018
Start with omitting the clear all, because this is a waste of time only. The error message is clear: Your t is the output of ode45() and a double vector. Then you cannot define t.FontSize. In the line before, the t would have been re-defined, but it is commented:
% t = text(0.0025, 17, txt);
Either delete the "%" character there or better use a unique name for the variable:
TestH = text(0.0025, 17, txt);
TextH.FontSize = 24;
It is not clear, what a "third legend" is. There is one legend only and not even a second one. Do you want to get a third entry in this legend? This would be confusing, because readers expect the same number of lines as legend entries. Maybe an additional title helps: https://www.mathworks.com/matlabcentral/answers/324848-setting-a-title-for-a-legend
  1 Kommentar
Vikash Pandey
Vikash Pandey am 13 Nov. 2018
Thanks for the advise. I corrected it. But still a minor issue remains. Please see above.

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Vikash Pandey
Vikash Pandey am 13 Nov. 2018
Yes. you see the plot here, mu looks so different than m in the plot. I want them to be latex equally. By the way I have solved the bubble coupled ODE problem that I had posted yesterday. Hope you remember. :)
Similar_Size_Far_Radius.png

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