I have a problem regarding finding a maximum value from my matrix (largest element in the row)
I have matrix A shown bellow
I know that I can use
M=max(A,[],2)
Then I will get matrix M such that
But the answer I want is not that, what I want is that . The one that I want is
The answer that I want is the maximum value of each row ignoring the negativity of each value like shown in the matrix above.
I hope my question is clear enough.

 Akzeptierte Antwort

Stephen23
Stephen23 am 6 Aug. 2018
Bearbeitet: Stephen23 am 6 Aug. 2018

0 Stimmen

This can be done using sub2ind:
A = [2,4,-1,0,-1;1,3,12,-3,2;-12,2,4,0,-1;2,4,0,-5,-2;3,-4,-1,0,8]
[~,C] = max(abs(A),[],2); % C = column indices
S = size(A);
R = 1:S(1); % R = row indices
X = sub2ind(S,R(:),C(:)); % X = linear indices
Z = A(X)
Giving
Z =
4
12
-12
-5
8
It would be nice if max etc. could return the linear indices, but that is what we have to work with. Note that you can also calculate the linear indices yourself, without sub2ind:
X = S(1)*(C-1)+(1:S(2)).'

2 Kommentare

Thanks for the answer, it works for me
Another possibility:
>> A = [2,4,-1,0,-1;1,3,12,-3,2;-12,2,4,0,-1;2,4,0,-5,-2;3,-4,-1,0,8];
>> [C,X] = max(max(cat(9,A,-A),[],2),[],9);
>> C .* (3-2*X)
ans =
4
12
-12
-5
8

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Fangjun Jiang
Fangjun Jiang am 6 Aug. 2018

0 Stimmen

use abs() and note that the second return of max() gives the indices. See if you can figure it out.

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