How do I get the last element of a cell array from a function call?

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Say I am making a function call to a function that needs an index as one of its arguments, however, in this case, I only want the last element of the cell array. So far I have this:
twin_start = boundary_times(df,steplists,stepIdx,full_step_str,end);
using end as an argument, but I know you can't use end like that. Is there something I can do to indicate that I want the last element of the cell array when making a function call? Thank you :)
  2 Kommentare
Rik
Rik am 15 Jul. 2018
You mean you want only the last element of your output array? I have no idea what kind of input boundary_times is expecting, so I can't tell if you should use some call to numel or something totally different.
Elizabeth Cisneros
Elizabeth Cisneros am 15 Jul. 2018
For the input I am talking about in boundary_times (location) it is just expecting an index
function twin_time = boundary_times(df,steplists,stepIdx,step_str,location)
and this is the array from boundary_times where that index will go in
%split time window string to determine end time
twinSplit = strsplit(step_twin,{' ','->'});
step_BoundaryT = twinSplit{location};
However, there are sometimes where the size of this cell array may vary (this is in a loop by the way) so I am trying to figure out a way to call it where the location input will always be the last element. I've tried length(twinSplit) too but that doesn't work.

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Akzeptierte Antwort

Stephen23
Stephen23 am 15 Jul. 2018
Bearbeitet: Stephen23 am 15 Jul. 2018
Write the function to accept a special case, e.g. an empty array indicates end:
if isempty(location)
step_BoundaryT = twinSplit{end};
else
step_BoundaryT = twinSplit{location};
end
and then call it like this:
boundary_times(...,[]);
  2 Kommentare
Elizabeth Cisneros
Elizabeth Cisneros am 15 Jul. 2018
Thank you, Stephen! I never thought about actually changing the function.
Image Analyst
Image Analyst am 16 Jul. 2018
Well changing the function was what I suggested to you in my earlier answer, but you said "I wouldn't want to hardcode it though because I use this function for other purposes". Glad to see you changed your mind. Obviously if nothing changes in your code (or input data), then nothing will change in the results.

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Weitere Antworten (1)

Image Analyst
Image Analyst am 15 Jul. 2018
Try this:
% Put contents of last cell of the twinSplit cell array into step_BoundaryT
step_BoundaryT = twinSplit{end};

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