How do I get the last element of a cell array from a function call?
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Elizabeth Cisneros
am 15 Jul. 2018
Kommentiert: Image Analyst
am 16 Jul. 2018
Say I am making a function call to a function that needs an index as one of its arguments, however, in this case, I only want the last element of the cell array. So far I have this:
twin_start = boundary_times(df,steplists,stepIdx,full_step_str,end);
using end as an argument, but I know you can't use end like that. Is there something I can do to indicate that I want the last element of the cell array when making a function call? Thank you :)
2 Kommentare
Rik
am 15 Jul. 2018
You mean you want only the last element of your output array? I have no idea what kind of input boundary_times is expecting, so I can't tell if you should use some call to numel or something totally different.
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Stephen23
am 15 Jul. 2018
Bearbeitet: Stephen23
am 15 Jul. 2018
Write the function to accept a special case, e.g. an empty array indicates end:
if isempty(location)
step_BoundaryT = twinSplit{end};
else
step_BoundaryT = twinSplit{location};
end
and then call it like this:
boundary_times(...,[]);
2 Kommentare
Image Analyst
am 16 Jul. 2018
Well changing the function was what I suggested to you in my earlier answer, but you said "I wouldn't want to hardcode it though because I use this function for other purposes". Glad to see you changed your mind. Obviously if nothing changes in your code (or input data), then nothing will change in the results.
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Image Analyst
am 15 Jul. 2018
Try this:
% Put contents of last cell of the twinSplit cell array into step_BoundaryT
step_BoundaryT = twinSplit{end};
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