Difference between mod and rem functions
197 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
May i know why is mod(4,-3)
ans =
-2
>> rem(4,-3)
ans =
1
these two answers different?
1 Kommentar
Ignacy Szkudelski
am 29 Nov. 2019
Note: REM(x,y), for x~=y and y~=0, has the same sign as x.
mod(x,y) and REM(x,y) are equal if x and y have the same sign, but
differ by y if x and y have different signs.
Antworten (2)
Stephen23
am 4 Jun. 2018
Bearbeitet: Stephen23
am 4 Jun. 2018
The outputs of rem and mod are the same if the inputs have the same sign, otherwise it depends on how the division is interpreted. The MATLAB documentation states that "The concept of remainder after division is not uniquely defined, and the two functions mod and rem each compute a different variation. The mod function produces a result that is either zero or has the same sign as the divisor. The rem function produces a result that is either zero or has the same sign as the dividend."
The mod function's output is periodic, so this is useful where the periodicity is important (e.g. signal processing). You can also use this behavior for a simple test if a value is odd:
>> mod(-3,2)==1 % yes, -3 is odd!
ans = 1
>> rem(-3,2)==1 % does not work!
ans = 0
2 Kommentare
Stephen23
am 5 Jun. 2018
Bearbeitet: Stephen23
am 30 Nov. 2019
"...does it mean that mod and rem both calculates the remainder but in a different way?"
Yes. Because there are different concepts of what "remainder" means for negative values. There is no "correct" definition, because both of them are useful in different situations: rem gives the remainder that people might think of when asking themselves "divide the input Q times, what remains?", whereas mod is perfectly periodic. Neither is better than the other, they just do different things.
"How do they actually work?"
- mod(a,b) is defined as a-b.*fix(a./b)
- rem(a,b) is defined as a-b.*floor(a./b)
The difference is clear when you plot their outputs:
>> X = -10:0.1:10;
>> plot(X,mod(X,4))
>> title('mod')
![mod.png](https://www.mathworks.com/matlabcentral/answers/uploaded_files/251605/mod.png)
Versus
>> X = -10:0.1:10;
>> plot(X,rem(X,4))
>> title('rem')
![rem.png](https://www.mathworks.com/matlabcentral/answers/uploaded_files/251606/rem.png)
Jan
am 4 Jun. 2018
Bearbeitet: Jan
am 4 Jun. 2018
See: doc rem and doc mod:
mod is: r = a - b .* floor(a ./ b)
rem is: r = a - b .* fix(a ./ b)
This is the same for positive values, but differs by b for negative values. floor is the next smaller integer, fix is removing the fractional part.
3 Kommentare
Jan
am 5 Jun. 2018
@Lorenne: The complete behavior is explained exhaustively in the documentation. See:
doc rem
doc mod
doc fix
As described there (and mentioned by Stephen already), fix rounds towards zero. "6/4" is stored as 1.5 in Matlab. Then removing the fractional part means to set all digits right from the decimal point to zero. Try it:
fix(1.5)
>> 1
Siehe auch
Kategorien
Mehr zu Assumptions finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!