Why I get Reference to a cleared variable x. in my code?

function data=surface_point(x,y)
clc, clear all, close all
px = [0 50 100 150 200 250 300; 0 50 100 150 200 250 300; 0 50 100 150 200 250 300; 0 50 100 150 200 250 300];
py = [0 0 0 0 0 0 0; 50 50 50 50 50 50 50;100 100 100 100 100 100 100;150 150 150 150 150 150 150];
pz = [-15 70 90 -60 -40 15 40; 40 -5 -20 -40 50 30 -20; 0 -45 -30 30 40 -10 -40; -30 5 50 0 -30 -20 20];
n=size(px,1)-1;
m=size(px,2)-1;
c=30;
u = x/300;
v = y/150;
for i=1:n+1
for j=1:m+1
sx=sx+px(i,j)*B(i-1,n,u)*B(j-1,m,v);
sy=sy+py(i,j)*B(i-1,n,u)*B(j-1,m,v);
sz=sz+pz(i,j)*B(i-1,n,u)*B(j-1,m,v);
end
end
data = [sx sy sz];

2 Kommentare

Stephen23
Stephen23 am 2 Mär. 2018
Bearbeitet: Stephen23 am 2 Mär. 2018
"Why I get Reference to a cleared variable x. in my code?"
Because for no reason at all you put
clc, clear all, close all
at the start of your function. Why use some commands in your function if you don't know what they are doing? How are these commands in any way related to the functionality of what you are writing?
He probably wrote this without a function wrapper and forgot to remove that line before adding the function definition, having decided to wrap that code in a call.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Image Analyst
Image Analyst am 2 Mär. 2018
Because, although you pass in x and y, you delete them immediately with the command
clear all
Don't do that!!! If you don't do that, x will still be there when you need to use it.

Weitere Antworten (0)

Kategorien

Mehr zu Entering Commands finden Sie in Hilfe-Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by