Filter löschen
Filter löschen

Storing a range as a variable

106 Ansichten (letzte 30 Tage)
Steeven
Steeven am 26 Feb. 2018
Bearbeitet: Stephen23 am 26 Feb. 2018
Imagine the start and end values of a range being set from user input. They could be:
a=3;
b=10;
To extract this range from an array, I simply do:
x(a:b);
But I'd like to save this range as one variable in itself, so that I can insert the range easily many places and only have to change it in one place such as:
range=a:b;
x(range);
This gives an error. MatLab will not store the a:b in this manner since : is a string and I thus am mixing strings with numbers. I could convert the a and b into a string with num2str, but then that range cannot be inserted into the x variable.
Is there a way to do this or do I have to manually put together the range with x(a:b) every time?
  2 Kommentare
Adam
Adam am 26 Feb. 2018
range = a:b;
is perfectly acceptable syntax. : is an operator here, not a string.
Stephen23
Stephen23 am 26 Feb. 2018
Bearbeitet: Stephen23 am 26 Feb. 2018
"This gives an error."
Not when I try it:
>> a = 3;
>> b = 10;
>> range = a:b
range =
3 4 5 6 7 8 9 10
See also the earlier question:

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Angelo
Angelo am 26 Feb. 2018
x=[0.1:0.1:2];
range=[3:10];
x(range)
  1 Kommentar
Jan
Jan am 26 Feb. 2018
See: http://www.mathworks.com/matlabcentral/answers/35676-why-not-use-square-brackets . The additional square brackets waste time only. They are the concatenation operator, but "3:10" is a vector already and nothing is concatenated.
In addition it is worth to consider, that
x(a:b)
is faster than
v = a:b;
x(v)
because in the first case, the index vector a:b is not created explicitly.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Jan
Jan am 26 Feb. 2018
Bearbeitet: Jan am 26 Feb. 2018
What's wrong with
x(a:b)
You really need to store it in one variable?
Range.a = a;
Range.b = b;
x(Range.a : Range.b)
Or:
Range = {a,b};
x(Range{1}:Range{b})
You could write a function also:
GetInterval(x, Range)
function y = GetInterval(x, Range)
y = x(Range{1}:Range{b});
end
But this will be slower and worse to read than the direct and simple:
x(a:b)
Note that Matlab seems to avoid the explicit creation of the index vector a:b to save time in this case, but this is not documented.

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by