Filter löschen
Filter löschen

I am having trouble computing this problem in matlab. How do I compute AA^-1 and print out the product where A is the 9x9 matrix?

2 Ansichten (letzte 30 Tage)
A=[ai,j] , ai,j=1/i+j-1. So far I have i=4 and j=5
  1 Kommentar
John D'Errico
John D'Errico am 5 Dez. 2017
Please don't add answers, when all you want to do is make a comment. In my comment, I even said that was what you are asked to compute. Thus, it seems clear that the homework problem you have been assigned was to...
Compute the 9x9 hilbert matrix, thus the square matrix A(i,j), such that
A(i,j) = 1/(i+j-1)
Then compute the inverse of that matrix and multiply the two. Is the product an identity matrix, as theory suggests it should be? If not, then you might be asked to conjecture as to why it is not so. This might be the subject of further class discussions and/or homework assignments.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Image Analyst
Image Analyst am 4 Dez. 2017
Uh,
i=4
j=5
will not do
A=[ai,j]
ai,j=1/i+j-1
I don't know exactly what operation you were hoping for, but that code won't do it. Why don't you try in a for loop over j. Then you'll need to define what ai is. the second line of code only defines j to be (1/i) + j + 1, it does NOT define ai at all, and hence when you try to use it as a row vector in [ai,j] it will fail because ai was never defined.
Also, what exactly is "AA^-1" - can you describe in words what operation(s) this is?
  3 Kommentare
John D'Errico
John D'Errico am 4 Dez. 2017
Bearbeitet: John D'Errico am 5 Dez. 2017
I was surprised too. Surely a reflection of the pure quality of your answers, even when you were totally confused yourself.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu MATLAB finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by