Finding columns in a cell array containing finite elements

Hi, I have a m*n cell array containing x and y coordinates , suppose K is a 3*2 cell array as follows:

K=

[Inf] [1x2 double] [Inf]

[Inf] [ Inf] [1x2 double]

[Inf] [Inf] [Inf]

I want to access the columns of the array that are not infinite. My aproach: find([K{f,:}]< inf) returns columns as 2,3 for the first row. I want the result to be just 2. The x and y coordinates occur at random positions.

Is there any way to find the columns of the cell array?

Thanks

Answer 1

[Guillaume]

cellfun(@(x) all(isfinite(x)), K)

will return a logical array telling you whether each cell of K contains only finite values. You can pass that to find if you do need to know the rows or columns. Most time, using the logical array as a filter is faster.

[Himanshi Rani]

Is there any way to do this without converting it to a logical array?

[Stephen23]

@Himanshi Rani: using logical indexing is likely the simplest and most efficient way of doing this.

[Guillaume]

@Himanshi Rani, every time you use find, you are using a logical array. In your original approach find([K{f,:}]< inf), the [K{f,:}]< inf is a logical array.