Add matrix to matrix
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ha ha
am 30 Aug. 2017
Bearbeitet: Stephen23
am 1 Sep. 2017
Let's say: A=zeros(7,2):
A=[ 0 0
0 0
0 0
0 0
0 0
0 0
0 0]
B=[4 1 3] ; C=[1 1 1] ;
D=[2 5 7 6]; E=[2 2 2 2]
How can I add two matrix B,C,D,E to matrix A to get the result as follows:
F=[ 4 1 ......add B, C.......
1 1 ......add B, C.......
3 1 ......add B, C.......
2 2 ......add D, E.......
5 2 ......add D, E......
7 2 ......add D, E......
6 2] ......add D, E......
In general, let's say :
A=zeros(1000,2)
B1=[1; 2; 3;....100] ; index_B1= [1;1;1;.....1] {100 element 1}
B2=[101;102;103....300]; index_B2= [2;2;2;.....2] {200 element 2}
B3=[301;302;303....600]; index_B3= [3;3;3;.....3] {300 element 3}
..................................................................
B7=[801;802;803....850]; index_B7= [7;7;7;.....7] {50 element 7}
...................................................................
Bi=[921;922;923....1000]; index_Bi=[i;i;i;.....i] {80 element i}
1/ How to create matrix index_Bi according to the number of element in matrix Bi? (If possible please use while or for ...loop to do)
2/ After that, How to add two matrices (Bi & index_Bi) to matrix A, we will have the result:
F=[ B1 index_B1
B2 index_B2
B3 index_B3
..............
B7 index_B7
.............
Bi index_Bi]
1 Kommentar
Akzeptierte Antwort
Andrei Bobrov
am 30 Aug. 2017
Bearbeitet: Andrei Bobrov
am 30 Aug. 2017
B = {B1;B2;B3;B4...;Bi}; % Please create B array.
n = cellfun(@numel,B);
A = [cell2mat(B),repelem((1:numel(n))',n)];
5 Kommentare
Guillaume
am 31 Aug. 2017
You should never have matrix B1, B2, ... Bn in your workspace. As soon as you start numbering matrices, you should stop and change the way you work. These numbered matrices are obviously relatedm they should therefore be stored together into a single container variable such as the cell array that Andrei used.
Weitere Antworten (2)
KL
am 30 Aug. 2017
N = [B.' C.';
D.' E.'];
F = A+N
Why E has only 3 elements? I'd assume you missed out something there.
1 Kommentar
Guillaume
am 30 Aug. 2017
In your particular example, and assuming that E is supposed to have 4 elements instead of the 3 you've written:
F = A + [B.', C.'; D.', E.']
I have no idea where you're going with this question, so can't answer in a generic way.
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