I am trying to calculate the response of a vibrating cantilever beam using ode45 function. There is no error in the code but when i run the code it takes to long to produce the result. I am not sure where i made a mistake. Can someone help me
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Aravind Krishnamoorthi
am 21 Aug. 2017
Kommentiert: Mia Finit
am 26 Nov. 2021
MATLAB code
width = 5;
height = 0.1;
% The material is steel
E = 3.0e7;
nu = 0.3;
rho = 0.3/386;
% Calculate the coefficient matrix from the material properties
%G = E/(2.*(1+nu));
%mu = 2.0*G*nu/(1-nu);
I = height^3/12;
A = height*width;
% From beam theory, there is a simple expression for the lowest vibration
% frequency of the cantilever beam.
omegasq = 7.885^4*E*I/(rho*A*width^4);
beam=@(t,y)[y(2);(-(2*1*omegasq*y(2))-(omegasq^2*y(1)))];
ic= [0;5];
tspan = [0:5];
[t,y]=ode45(beam,tspan,ic);
plot(t,y), title ('Time vs Displacement')
grid on
hold on
0 Kommentare
Akzeptierte Antwort
Steven Lord
am 21 Aug. 2017
Your problem is stiff. Let's substitute in symbolic values for y and see what your ODE function will return.
>> vpa(beam(1, [sym('y1'); sym('y2')]))
ans =
y2
- 1583163086609297.0*y1 - 79577963.950060874223709106445312*y2
A small change in either y1 or y2 results in a huge change in dy2/dt and thus a huge change in y2 at the next time step. So the ODE solver needs to take very, very small steps. You can see this if you plot your ODE:
[t,y]=ode45(beam,tspan,ic, odeset('OutputFcn', @odeplot));
Let that run for a minute or two and see that progress is being made, but it is being made very slowly. You may want to zoom in around y = 0, x between 0 and 0.01. Now let's try this same experiment but with a stiffer solver like ode15s:
[t,y]=ode15s(beam,tspan,ic, odeset('OutputFcn', @odeplot));
The plot (and the ODE solver) finished too quickly for me to see the individual time steps being plotted except as a bit of flicker.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Ordinary Differential Equations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!