remove elements from cell
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Dear all, I know, I've asked alot and I really appreciate your help. I have a cell array:
a = {[1 2 3 55 77 8] [3 77] [ 1 2 5 7 8 9 0 2] [ 3 44 6]}
and I would like to remove the numbers before the index based on vector b=[3 9 6]. The expected answer should be:
cell2 = {[55 77 8] [77] [0 2] []}
Thanks.
1 Kommentar
Jan
am 13 Jul. 2017
Bearbeitet: Jan
am 13 Jul. 2017
It is very welcome if you ask many questions here. But it would be appreciated, if you explain the problem as detailed as needed to define it uniquely. The explanation "remove the numbers before the index based on vector b=[3 9 6]" is not clear. Then showing any own effort and asking a specific question concerning your code would be useful also, for you and for the readers.
Antworten (2)
Image Analyst
am 12 Jul. 2017
This will do it:
a = {[1 2 3 55 77 8] [3 77] [ 1 2 5 7 8 9 0 2] [ 3 44 6]}
b=[3 9 6]
% cell2 = {[55 77 8] [77] [0 2] []}
for k = 1 : length(a)
thisArray = a{k}; % Extract array from cell.
[inA, inB] = ismember(b, thisArray); % Find where any of b occurs in thisArray.
index = find(inB>0, 1, 'last'); % Find last occurrence.
outputArray = thisArray(inB(index)+1:end); % Extract out to new array.
cell2{k} = outputArray; % Stuff into a new cell array.
end
celldisp(cell2); % Display in command window.
It's easy and intuitive, though I'm sure someone will give you a cryptic one-liner shortly.
3 Kommentare
dbmn
am 13 Jul. 2017
skysky could you tell us what didnt work in your case?
image_analyst: one liner coming up
cell2 = cellfun(@(x) x(max([find(ismember(x, b),1, 'last'), 0])+1:end), a, 'uni', 0);
p.s. when you use max([index, 0]) you can get rid of the empty matrices :)
skysky2000
am 13 Jul. 2017
2 Kommentare
Image Analyst
am 13 Jul. 2017
I gave you help. My code produced exactly the cell array that you said you wanted. What's the problem? Prove to me that it does not give you what you asked for, because I don't know what else to do.
Jan
am 13 Jul. 2017
@skysky2000: Please do not bump your thread by posting a pseudo-answer. The question is not really clear, but Image Analysts has posted a method to produce the requested answer. Now it is your turn to explain, which details is not solved yet.
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