I think this i quite easy for you guys - but ive not found an answer yet (perhaps because my english skills are limitated) I want to summ up two vektors like this V1 = [1 2 3] V2 = V1' (the transposed vektor) and I want to get the ?inner? sum
1 2 3
1
2
3
so that i get a matrix with this relsult ( so just row plus column )
2 3 4
3 4 5
4 5 6
would be really nice if you can help me. thx a lot

2 Kommentare

John D'Errico
John D'Errico am 12 Apr. 2017
You called this an inner sum. But really, the correct term would be a generalized outer product.
https://en.wikipedia.org/wiki/Outer_product
James Tursa
James Tursa am 12 Apr. 2017
Bearbeitet: James Tursa am 12 Apr. 2017
OP is summing, not multiplying. I.e., an "outer sum" not an "outer product"

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 Akzeptierte Antwort

Star Strider
Star Strider am 12 Apr. 2017

1 Stimme

Use the bsxfun function with the @plus function:
A = [1 2 3];
B = bsxfun(@plus, A(:), A)
B =
2 3 4
3 4 5
4 5 6
(In R2017a, this implicit expansion is done automatically. I still prefer bsxfun because it will throw an error if I do something wrong.)

2 Kommentare

Sean de Wolski
Sean de Wolski am 12 Apr. 2017
How would bsxfun throw an error that implicit expansion won't?
Star Strider
Star Strider am 12 Apr. 2017
I’ve not tried implicit expansion without bsxfun. I’m in no rush to do so.

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Weitere Antworten (2)

Guillaume
Guillaume am 12 Apr. 2017

2 Stimmen

If you're using R2016b or later, simply
V1 + V1.'
In earlier versions
bsxfun(@plus, V1, V1.')
Paul Hoffmann
Paul Hoffmann am 13 Apr. 2017

0 Stimmen

thx for the answer - helped a lot !

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