I have a function of x and t, and am creating a loop to find the average x/t for every U. I have successfully used this method before, however my x values are zero every time.
My function is:
function dx=myfunction(t,x,U)
de=24.35;
dd=294.5.*10^(-9);
hbar=6.5.*10^(-16);%
lambda=20*d;
k=(2.*pi)/(lambda);
v=2.5.*10^(-3);
dx=zeros(3,1);
dx(1)=((de)/(2.*hbar.*v.*k)).*sin(x(2));
dx(2)=(dd.*U)./(hbar.*2*v).*(cos(((pi.*x(1))/10)-(t)));
end
In the loop:
dU=1;
U=0:dU:200;%
tspan=[1 30];
vx=zeros(size(U));
for j=1:length(U)
[t,x]=ode45(@(t,x) myfunction(t,x,U(j)),tspan,[0 0 0]);
vx(j)=(sum((x(:,1))./(t))./(length(t));
end
Any ideas as to why the changing of U gives x a value of 0 would be useful.
Thanks in advance.

3 Kommentare

Stephen23
Stephen23 am 2 Mär. 2017
You managed to name a function function? I am amazed that that works.
Physics
Physics am 2 Mär. 2017
Bearbeitet: Physics am 2 Mär. 2017
I have edited the constants and names. Changed it for ease.
Jan
Jan am 3 Mär. 2017
Note: While dd=294.5.*10^(-9) is an exüpensive power operation, dd=294.5e-9 is a cheap constant.

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Antworten (1)

Jan
Jan am 3 Mär. 2017

1 Stimme

The code will not run at all, because the number of parenthesis in
vx(j) = (sum((x(:,1))./(t))./(length(t));
is wrong. I guess you want:
vx(j) = sum(x(:,1) ./ t) ./ length(t);
It is useful to use additional parenthesis, if it improves the readability of the code, but here this was an overdoing.
If this is fixed, runnign your code fails in the line:
lambda=20*d;
due to an undefined variable "d".
Finally all I can suggest to use the debugger to examine, what's going on. Set a breakpoint in your code and step through the program line by line. This helps to understand, where which values are defined. Please post the running code afterwards, if you still have problems.

2 Kommentare

Physics
Physics am 3 Mär. 2017
Thanks so much for taking the time to look at this.
These issues again are from my editing to create this post - they would clearly show as errors when running!
I was getting 0 values from the size of my range, as a solution for your interest.
Thanks again!
Walter Roberson
Walter Roberson am 4 Mär. 2017
If you are still having difficulty, please post corrected code.

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