Calculate each object maximum height and weight
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Ely Raz
am 2 Feb. 2017
Kommentiert: Image Analyst
am 4 Feb. 2017
How can I calculate each object maximum height and weight in the following example?
I used this code:
clc;
clear;
I = rgb2gray(imread('http://i67.tinypic.com/14jxq0y.jpg'));
adpt1 = imbinarize(I);
adpt1 = imfill(adpt1, 'holes');
[B,L] = bwboundaries(adpt1,'noholes');
stat = regionprops(adpt1,'All');
imshow(adpt1);
hold on
for k = 1 : length(B)
b = B{k};
c = stat(k).Centroid;
plot(b(:,2),b(:,1),'g','linewidth',3);
text(c(1),c(2),num2str(k),'backgroundcolor','g');
end
1 Kommentar
Walter Roberson
am 2 Feb. 2017
You have curved objects.
For "height" are you looking for the height of the highest point minus the height of the lowest point?
Are you looking to do the equivalent of running a ruler horizontally along the figure and examine the maximum point minus the minimum point at each column, and find the largest difference amongst those -- the "thickest" vertical?
In your object #4, top center, the left side is concave, so if you did that you would have a gap along the vertical line: is only the solid part to be counted, or the furthest reaches?
Are you looking to find the maximum axes and the axes 90 degrees to that? For example in object #6, right center, the maximum axis is along the diagonal from top left to bottom right: is that one of the distances to be measured, and then the other would be the diagonal from bottom left to top right?
Akzeptierte Antwort
Image Analyst
am 2 Feb. 2017
Ask regionprops to return the Bounding Box.
In the loop
thisBB = stats(k).BoundingBox
thisWidth = thisBB(3);
thisHeight = thisBB(4);
hold on;
rectangle('Position', thisBB, 'EdgeColor', 'c');
6 Kommentare
Walter Roberson
am 4 Feb. 2017
Bearbeitet: Walter Roberson
am 4 Feb. 2017
Hee. I see you've started using my naming practice of " this such and such" ;-)
Image Analyst
am 4 Feb. 2017
I think I picked that up in 2003 when I learned Java. I thought it was a good idea so I use it occasionally.
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