array fetching and placing in matrix
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Bathrinath
am 6 Sep. 2016
Bearbeitet: Stephen23
am 6 Sep. 2016
I have a matrix c = [0 0 0; 0 0 0; 0 0 0] from the command c=zeros(3,3). My array p=[12,10,11,13,8,9,5]; I need to get array in c and my final value of c should be [12,10,11;9,13,8;0,0,5]. First 3 array value should be placed in first row of c, in the second row of c, it has to look the minimum value in the first row (min value =10) corresponding column it has to place the fourth value in array. Similarly fifth and sixth value in array p is placed. now in the third row of matrix c, first two rows of c has to be added to get the minimum value. after the summation minimum value is in third column so the seventh value in the array p is placed in third column of matrix c. This procedure has to be done irrespective of the array size and matrix. kindly suggest.
2 Kommentare
Guillaume
am 6 Sep. 2016
I don't understand your algorithm. Why, when the minimum of the first row is 10, do you select the 6th value (equal to 9) of p to place in C(2, 1)?
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Stephen23
am 6 Sep. 2016
Bearbeitet: Stephen23
am 6 Sep. 2016
Edit works for input matrices of any size:
% input data:
p = [12,10,11,13,8,9,5];
c = zeros(3,3);
% input sizes:
[row,col] = size(c);
len = numel(p);
% allocate data:
c = c.';
idx = 1:min(len,row*col);
c(idx) = p(idx);
c = c.';
% sort rows:
for k = 2:row
[~,idx] = sort(c(k-1,:));
c(k,idx) = c(k,:);
end
creates this:
>> c
c =
12 10 11
9 13 8
0 0 5
5 Kommentare
Stephen23
am 6 Sep. 2016
Bearbeitet: Stephen23
am 6 Sep. 2016
@Bathrinath: like any skill, learning how to create and implement algorithms takes time and practice. You can start learning how to use MATLAB by doing these tutorials:
and read this carefully:
The best thing you can do is to practice and learn to read the documentation: MATLAB has excellent documentation, with lots of working examples and articles explaining many topics. Learn how to navigate it, browse the contents hierarchy, and use the links effectively.
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