remove rows by pick the min value in another column

Can you help?
On below matrix, for same X and Y, pick smallest Z, then put into a new matrix by removing the rows? and also give the row number for which row is kept.
X Y Z
60,-40,1.1
55,-40,3.1
55,-45,4.5
60,-45,5.3
60,-40,7
55,-40,8.4
55,-45,9.8
60,-40,11.2
60,-45,12.6
55,-40,14
55,-45,15.4
60,-45,16.8
60,-40,18.2
60,-45,19.6
55,-40,21
60,-40,22.4
55,-45,23.8
60,-45,25.2
55,-40,26.6
55,-45,28

5 Kommentare

I can think of at least two ways. How many can you think of?
And Jos thought of another the first time you asked this question. What was wrong with his answer?
booterr
booterr am 15 Apr. 2016
Bearbeitet: booterr am 15 Apr. 2016
can you also give the row number for which row is kept?
Output the row number (or row index)which is kept. For example, there is a total of 20 rows in the question. Finally, only row 1,2,3, and 4 is kept. Can you output this row number?
booterr
booterr am 15 Apr. 2016
not a duplicate questions. For the first thread, the answer did not give which row number the Z is located in the initial matrix.
I am not only needing the value of Z, but also need the row number of which Z is outputted.
thanks

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 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 15 Apr. 2016
Bearbeitet: Andrei Bobrov am 15 Apr. 2016
x=[55,-45,9.8
60,-40,11.2
60,-45,12.6
55,-40,14
55,-45,15.4
60,-45,16.8
60,-40,18.2
60,-45,19.6
55,-40,21
60,-40,22.4
55,-45,23.8
60,-45,25.2
55,-40,26.6
55,-45,28]
[a,~,c] = unique(x(:,1:2),'rows');
n = size(a,1);
valuemin = zeros(n,4);
for ii = 1:n
i0 = find(c == ii);
[valuemin(ii,3),i1] = min(x(i0,end));
valuemin(ii,[1:2,4]) = [a(ii,:),i0(i1)];
end
or
[a,~,c] = unique(x(:,1:2),'rows');
idx = accumarray(c,(1:size(x,1))',[],@(y)y(min(x(y,3))==x(y,3)));
valuemin = [a,x(idx,3),idx];

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am 14 Apr. 2016

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am 15 Apr. 2016

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