How to join character

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Pat
Pat am 27 Mär. 2016
Kommentiert: Walter Roberson am 28 Mär. 2016
I have a string, after preprocessing i get result as
str=Institution/College
Name;
When i split the string using
str1=regexp(str, '/', 'split')
i get result as [1x11 char] [1x11 char]
str2{2}
gives
College
Name
i need as College Name, i need in one line as College Name
Kindly help

Antworten (3)

Image Analyst
Image Analyst am 27 Mär. 2016
Well don't split it then. Or is the word Institution followed by a slash there and you just want to get rid of that?
str = 'Institution/College Name';
slashLocation = strfind(str, '/');
newStr = str(slashLocation+1:end) % Gives 'College Name'
  6 Kommentare
Walter Roberson
Walter Roberson am 28 Mär. 2016
find_system does not split the subsystem names at blanks. It returns a cell array of strings, each with one name. The adjacent entries do not belong together.
It sounds to me as if you have a carriage return (or newline) in a subsystem name. Historically that was not permitted. If it is permitted now, then the carriage return (or newline) would be part of the name and so the name should not be merged onto one line.
Walter Roberson
Walter Roberson am 28 Mär. 2016
It appears that under some conditions, spaces and newlines are now permitted; http://www.mathworks.com/help/simulink/ug/accessing-signal-logging-data.html#budgyrh . However, they would still be part of the name. It would be valid to have a signal named 'College Name' (with a space) and a signal named ['College' char(10) 'Name'] (with a newline) in the same block, so putting them on the same line would be misrepresenting the name.

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KSSV
KSSV am 27 Mär. 2016
Doc strcat
  1 Kommentar
Pat
Pat am 27 Mär. 2016
sorry str2{2} gives
College
Name
i need as College Name,strcat doesn't provide result i tried using strcat ,but the result is one string in two lines,i need in one line

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Stephen23
Stephen23 am 28 Mär. 2016
Bearbeitet: Stephen23 am 28 Mär. 2016
>> old = sprintf('Institution/College\nName')
old = Institution/College
Name
>> new = regexp(regexprep(old,'\s+',' '),'/','split');
>> new{:}
ans = Institution
ans = College Name

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