"Subscripted assignment dimension mismatch" Please correct my program. tell me idea/logic to make sequence
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Triveni
am 22 Feb. 2016
Kommentiert: Stephen23
am 23 Feb. 2016
s = [30 30 30 30 30 30 0 0 0 0];
s = sort(s, 'descend'); %sorting sequence s
uniques = unique(s); % finding unique elements
for k = 1: length(uniques)
ua(:,:,k) = repmat(uniques(:,k),1 ,(length(s))); %repeating unique values for combine
end
for k= 2:length(s)
for j = length(s)-2:-1:1
for l = 1:6
ua1(:,:,1) = [ua(1, 1:j, 1), ua(1, 1:k, 2)]; %cut and combine values
end
end
end
output ua1
ua1 =
0 0 0 0 0 0 0 0 30 30
my loop for ua1 is not working. please help me.
I want to generate sequence
ua1(:,:,1) = [0 0 0 0 0 0 0 0 30 30];
ua1(:,:,2) = [0 0 0 0 0 0 0 30 30 30];
ua1(:,:,3) = [0 0 0 0 0 0 30 30 30 30];
ua1(:,:,4) = [0 0 0 0 0 30 30 30 30 30];
ua1(:,:,5) = [0 0 0 0 30 30 30 30 30 30];
ua1(:,:,6) = [0 0 0 30 30 30 30 30 30 30];
or if possible tell me trick to make
[0 0 0 0 0 0 0 0 0 30;
0 0 0 0 0 0 0 0 30 30;
0 0 0 0 0 0 0 30 30 30;
0 0 0 0 0 0 30 30 30 30;
0 0 0 0 0 30 30 30 30 30;
0 0 0 0 30 30 30 30 30 30;
0 0 0 30 30 30 30 30 30 30;
0 0 30 30 30 30 30 30 30 30;
0 30 30 30 30 30 30 30 30 30];
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Akzeptierte Antwort
Stephen23
am 22 Feb. 2016
Bearbeitet: Stephen23
am 22 Feb. 2016
Don't waste time with all of those loops when you can simply use hankel to generate the whole matrix:
>> hankel(zeros(1,9),[0,30*ones(1,9)])
ans =
0 0 0 0 0 0 0 0 0 30
0 0 0 0 0 0 0 0 30 30
0 0 0 0 0 0 0 30 30 30
0 0 0 0 0 0 30 30 30 30
0 0 0 0 0 30 30 30 30 30
0 0 0 0 30 30 30 30 30 30
0 0 0 30 30 30 30 30 30 30
0 0 30 30 30 30 30 30 30 30
0 30 30 30 30 30 30 30 30 30
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Weitere Antworten (1)
Walter Roberson
am 22 Feb. 2016
ua1(:,:,1) = [ua(1, 1:j, 1), ua(1, 1:k, 2)]; %cut and combine values
In that code, 1:j will have one length for the first j, but for the next j would have a different length. Therefore for different iterations of j, the right hand side will be different sizes, but each time you try to write it to the same size on the left.
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