how to identify each digit of a number?

Is there some way to identify each digit of a number? example: number 1001, digit one=1, digit two=0,digit three=0, digit four=1. i appreciate the help thanks

[jgg]

Why exactly do you want to do this?

You could just make an array which stores the digits:

 n = 1249;
 n_s = num2str(n);
 l = length(n_s);
 digits = zeros(1,l);

 for i = 1:l
    digits(i) = str2num(n_s(i));
 end

You could also do this without casting to a string, using modulo, but it's not clear why you want to do this in the first place, and this is a very flexible way to operate on vectors of information.

[James Tursa]

Are you interested in only integers (relatively simple solutions exist), or fractional numbers (non-trivial)?

[Lucas Santos]

I'm trying to solve the problem 4 project euler, I did not know the function num2str(x). This is going to increase in my reasoning. Thanks a lot guys, all comments helped me!

Answer 1

[Image Analyst]

Try this trick:

number = 1001
digits = num2str(number) - '0'

[Image Analyst]

If you have a decimal point in there like James mentioned, you can do this:

number = 1001.2345789
digits = sprintf('%f', number) - '0'
digits(digits<0) = [] % Get rid of decimal points.

[Gabrielle Rey]

what does the -'0' do? is this something you would only use for num2str?

[Stephen23]

"what does the -'0' do?"

Subtracts the character code for the character '0' (which happens to be 48) from the preceding array.

"is this something you would only use for num2str?"

No, as the Image Analysts comment demonstrates. Just as with numeric arrays, you can subtract character codes (in the form of character arrays) from character arrays, numeric arrays, or logical arrays.

[Image Analyst]

It subtracts the ASCII value of the character '0' from the ASCII values in the string.

So instead of '1001' being [49, 48, 48, 49], which is a numerical array of the ASCII values, it makes it [1, 0, 0, 1].