whats wrong with the code?

function fx=f(x)
for i=1:length(x)
if x(i)<0
fx(i)=x(i);
elseif x(i)==0:pi/2;
fx(i)=sin(x(i));
else
fx(i)=(sin(x(i)))
end
end
end

Antworten (2)

Thorsten
Thorsten am 7 Okt. 2015
Bearbeitet: Guillaume am 7 Okt. 2015

1 Stimme

x(i)==0:pi/2
compares x(i) to 0 and 1 (largest integer below pi/2) and gives the result in matrix of size 1x2. A matrix is considered to be true if all values are nonzero. Since x cannot be 0 and 1 at the same time, this never becomes true.
The code after else gives the same result as in the elseif before, so it does not make sense to differ between the two cases.
You don't need a for loop but you can use logical indexing to write your code, e.g.
fx(x<0) = x(x<0);
fx(x>=0 & x <= pi/2) = sin(x(x>=0 & x <= pi/2));
fx(x>pi/2) = -sin(x>pi/2);
Star Strider
Star Strider am 7 Okt. 2015

0 Stimmen

I would re-code your elseif line to:
elseif (x(i)>=0) & (x(i) <= pi/2)

1 Kommentar

Image Analyst
Image Analyst am 7 Okt. 2015
Why & instead of &&?

Diese Frage ist geschlossen.

Tags

Noch keine Tags eingegeben.

Gefragt:

am 7 Okt. 2015

Geschlossen:

am 20 Aug. 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by