Is there a function that returns a vector or array or list of values obtained by applying a function to margins of an array or matrix?
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For example, assume x is a vector of length n, and y is a vector of length m. I would like to construct the matrix the (n x m) matrix M(i,j) = f(x(i),y(j)). Of course I do not want to use loops!
Btw, in R, there is such a function (called apply).
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James Tursa
am 9 Jul. 2015
Bearbeitet: James Tursa
am 9 Jul. 2015
A bit clunky, but this works and makes no assumptions about f being vectorized:
n = numel(x);
m = numel(y);
M = arrayfun(@f,repmat(x(:),1,m),repmat(y(:)',n,1));
1 Kommentar
Bruno Remillard
am 9 Jul. 2015
John D'Errico
am 9 Jul. 2015
I'm surprised nobody mentioned this.
fun = @(x,y) sin(x+y);
x = 0:5;
y = (0:2:6)';
M = bsxfun(fun,x,y)
M =
0 0.84147 0.9093 0.14112 -0.7568 -0.95892
0.9093 0.14112 -0.7568 -0.95892 -0.27942 0.65699
-0.7568 -0.95892 -0.27942 0.65699 0.98936 0.41212
-0.27942 0.65699 0.98936 0.41212 -0.54402 -0.99999
3 Kommentare
James Tursa
am 9 Jul. 2015
Good as long as fun works with column vector inputs.
John D'Errico
am 10 Jul. 2015
Easy enough to ensure that X and Y are always the proper shapes.
M = bsxfun(fun,x(:).',y(:));
James Tursa
am 10 Jul. 2015
Bearbeitet: James Tursa
am 10 Jul. 2015
I guess I wasn't clear. bsxfun passes column vectors to the function, so whatever the function is, it must be able to deal with column vector inputs (i.e., it must be vectorized to this extent). That was the only point I was trying to make. It is similar to the f(X,Y) used in IA's solution ... f must be vectorized for this to work.
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