writing cellarray data into text file with specific tab space and precision.

cellArray =

    'p.1'    [38.141794059793398]    [31.983184186130529]    [1.751451095529832e+03]
    [ 10]    [38.094455446389709]    [31.940682658186898]    [1.779530219110660e+03]
    'ab1'    [38.162956465159276]    [32.019563510560964]    [1.542875077314675e+03]
    [ 20]    [38.176654734516106]    [32.068817577008474]    [1.389497182917781e+03]

 Name           Size            Bytes  Class     Attributes
 cellArray      4x4              1916  cell      global

% I need to write cellArray into text file as 3 tab space after the first column and 2 tab space between the numeric numbers. I need to get 8 numbers after the dot for numeric data.

% Thanks in advance.

[Jan]

What exactly are "3 tab spaces"? Three spaces or three tab characters?

Answer 1

[Jan]

C = {'p.1', 38.141794059793398, 31.983184186130529, 1.751451095529832e+03; ...
  10, 38.094455446389709, 31.940682658186898, 1.779530219110660e+03; ...
  'ab1', 38.162956465159276, 32.019563510560964, 1.542875077314675e+03; ...
  20, 38.176654734516106, 32.068817577008474, 1.389497182917781e+03}
% It took me time to edit the data in a clean syntax. Please do this by your own.

fid = fopen(FileName, 'w');
if fid == -1, error('Cannot open file for writing: %s', FileName);
Ct = C.';
fprintf(fid, '%s   %.8f  %.8f  %.8f\n%f %.8f  %.8f  %.8f\n', Ct{:});
fclose(fid)

Or with \t instead of teh spaces depending on what "tab spaces" means.

[sermet]

sorry for late reply. I applied your codes, it worked but numeric data in the first column (10,20) created into text file like 10.000000 20.000000. Is there a way to avoid this. I just need to write as 10 and 20.

[Jan]

Come on, Sermet. This is explained in the documentation of fprintf. Please take the time to read it. Simply replace the corresponding '%.8f' by '%d':

fprintf(fid, '%s   %.8f  %.8f  %.8f\n%f %d  %.8f  %.8f\n', Ct{:});

[sermet]

I'm sorry Simon. I don't know well about fprintf. But the result is still same when I replace '%.8f' by '%d': like; fprintf(fid, '%s %.8f %.8f %.8f\n%f %d %.8f %.8f\n', Ct{:});

[Stephen23]

@sermet: considering this and all of your other questions related to fprintf precision:

http://www.mathworks.com/matlabcentral/answers/213244-increasing-precison-using-fprintf-for-text-file

http://www.mathworks.com/matlabcentral/answers/137679-increasing-floating-point-for-cellfun-function

now would be a good time to read the documentation:

http://www.mathworks.com/help/matlab/ref/fprintf.html

The lovely people at TMW spent a lots of time writing it, and it contains lots of useful information!